(d) (e) Calculate the coefficient of Pearson correlation. If the surrounding temperature in the target installation location is averaged 55°C, argue whether the PE should be used for the piping systems. Support your answer with calculation using linear regression equation.

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter4: Eigenvalues And Eigenvectors
Section4.6: Applications And The Perron-frobenius Theorem
Problem 25EQ
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Question
(d)
(e)
Calculate the coefficient of Pearson correlation.
If the surrounding temperature in the target installation location is averaged 55°C,
argue whether the PE should be used for the piping systems. Support your answer
with calculation using linear regression equation.
Transcribed Image Text:(d) (e) Calculate the coefficient of Pearson correlation. If the surrounding temperature in the target installation location is averaged 55°C, argue whether the PE should be used for the piping systems. Support your answer with calculation using linear regression equation.
Q4
An engineer wants to investigate the effect of operating temperature to polyethylene (PE)
material reliability (in terms of Derating Factor, the higher the better, maximum value is
1.00) to be used for outdoor piping systems. Data are gathered as in Table Q4.
Table Q4
Experiment
no.
1
2
3
45
879
6
9
10
Operating temperature (°C), A Derating Factor, B
21
27
32
38
43
49
54
60
66
71
10
10
10
Given Σ 4 = 23801, Σ Β = 4.84, Σ AB; = 237.4
i=1
i=1
i=1
1.00
0.90
0.90
0.80
0.80
0.70
0.50
0.40
0.20
0.00
Transcribed Image Text:Q4 An engineer wants to investigate the effect of operating temperature to polyethylene (PE) material reliability (in terms of Derating Factor, the higher the better, maximum value is 1.00) to be used for outdoor piping systems. Data are gathered as in Table Q4. Table Q4 Experiment no. 1 2 3 45 879 6 9 10 Operating temperature (°C), A Derating Factor, B 21 27 32 38 43 49 54 60 66 71 10 10 10 Given Σ 4 = 23801, Σ Β = 4.84, Σ AB; = 237.4 i=1 i=1 i=1 1.00 0.90 0.90 0.80 0.80 0.70 0.50 0.40 0.20 0.00
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