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d-Has 10 molecuies/a x Q5: A) Derive Poisson's and Laplace's equations. B) Two infinite line currents I₁ = 6 az A at x=y=4 and I₂ = 3 āx A at z = 3, y = -6. Calculate B at (0, 0, 0). 06: magnetic field intensity may be

d-Has 10 molecuies/a x Q5: A) Derive Poisson's and Laplace's equations. B) Two infinite line currents I₁ = 6 az A at x=y=4 and I₂ = 3 āx A at z = 3, y = -6. Calculate B at (0, 0, 0). 06: magnetic field intensity may be

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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d- Has 10 molecules/mo xQ5: A) Derive Poisson's and Laplace's equations. B) Two infinite line currents I₁ = 6 az A at x=y=4 and I2 = 3 āx A at z = 3, y = -6. Calculate B at (0, 0, 0). 06: magnetic field intensity may be
Transcribed Image Text:d- Has 10 molecules/mo xQ5: A) Derive Poisson's and Laplace's equations. B) Two infinite line currents I₁ = 6 az A at x=y=4 and I2 = 3 āx A at z = 3, y = -6. Calculate B at (0, 0, 0). 06: magnetic field intensity may be
Ex2:-Two infinite line current I₁ = 2ay A at x = z = 4 and I₂ = 4āx at y-3, z =-6. Calculate Hat (0,0,0). Iy (hy) Solution :- At (0,0,0) then use H= a 1₂ 2πP₂ 4₁ = 2A P₁ = -4āx - 4āz, |p₁|=√32 āØ₁ =āl₁ Xāp₁ = ay X xã xi āØ₁ = (āz - āx) 4 √32 H₂ = 1₂ 2πP2 :. āØ₂ " H₁ = 2√32(a2-x)]=¹(az - āx) - a02 PART = ax x ap √32 √45 P₂ = −3āy+6āz, | p₂|=√45.ap₂ = y + z 32 جامع ارة - ax كلية الهندسة -āx 12 xay + ²)√45-az-2ay) 45m āz) √32 4 :: H₂ = 2^5 (2ãy + āz)]=[-2āy — āz] .. 2RV4545 :. H = H₂ + H₂= ay+ (1-5)āz 45m 8π ANI قسم الهندسة الكه AL EN H = -0.04āx -0.085ãy -0.002āz I A/m Foly
Transcribed Image Text:Ex2:-Two infinite line current I₁ = 2ay A at x = z = 4 and I₂ = 4āx at y-3, z =-6. Calculate Hat (0,0,0). Iy (hy) Solution :- At (0,0,0) then use H= a 1₂ 2πP₂ 4₁ = 2A P₁ = -4āx - 4āz, |p₁|=√32 āØ₁ =āl₁ Xāp₁ = ay X xã xi āØ₁ = (āz - āx) 4 √32 H₂ = 1₂ 2πP2 :. āØ₂ " H₁ = 2√32(a2-x)]=¹(az - āx) - a02 PART = ax x ap √32 √45 P₂ = −3āy+6āz, | p₂|=√45.ap₂ = y + z 32 جامع ارة - ax كلية الهندسة -āx 12 xay + ²)√45-az-2ay) 45m āz) √32 4 :: H₂ = 2^5 (2ãy + āz)]=[-2āy — āz] .. 2RV4545 :. H = H₂ + H₂= ay+ (1-5)āz 45m 8π ANI قسم الهندسة الكه AL EN H = -0.04āx -0.085ãy -0.002āz I A/m Foly
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