(d) It was found that 16.5 mL of a 0.5 M sulphuric acid (H2SO4) solution neutralised 25 mL of a given solution of sodium hydroxide (NaOH).

Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
Publisher:Skoog
Chapter16: Applications Of Neutralization Titrations
Section: Chapter Questions
Problem 16.20QAP
icon
Related questions
Question
Calculate the concentration of sodium hydroxide solution in g/l and in mol/L
(d) It was found that 16.5 mL of a 0.5 M sulphuric acid (H2SO4) solution neutralised
25 mL of a given solution of sodium hydroxide (NAOH).
25.0m.
PPI
M, =
16 5 x O.5 x2
25()
mi = 0.66 M
M, = 0.66M.
Transcribed Image Text:(d) It was found that 16.5 mL of a 0.5 M sulphuric acid (H2SO4) solution neutralised 25 mL of a given solution of sodium hydroxide (NAOH). 25.0m. PPI M, = 16 5 x O.5 x2 25() mi = 0.66 M M, = 0.66M.
Expert Solution
steps

Step by step

Solved in 2 steps

Blurred answer
Knowledge Booster
Concentration Terms
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Fundamentals Of Analytical Chemistry
Fundamentals Of Analytical Chemistry
Chemistry
ISBN:
9781285640686
Author:
Skoog
Publisher:
Cengage
EBK A SMALL SCALE APPROACH TO ORGANIC L
EBK A SMALL SCALE APPROACH TO ORGANIC L
Chemistry
ISBN:
9781305446021
Author:
Lampman
Publisher:
CENGAGE LEARNING - CONSIGNMENT