d? -(sin-'(x²)) dx2 2– 4x4 A 3 2– 2x4 B 3 2+2x4 3. 2+4x4 D

Q: 5- (tanx + secx)2 dx

A:

Q: Find [10] -t sin(v3t) е (а) L (b) L-- [tan-1 ))

A: We have to solve given problem:

Q: ( sinh3x cosh³x dx

A: Consider the integration as I=∫sinh3xcosh3xdx

Q: 17. sech? x tanhx dx 12

A: Integrated by substitutions

Q: sinhx dx 1+ coshx ) A 1+ coshx B (1+coshx)? (1+coshx)² D 1+ coshx

A: We have to find

Q: Find [(x- sin(2x)) dx

A:

Q: I-Shinx dx Ig-/sin'xdx 2-x2 dx

A: We have to evaluate the above integrals. NOTE - According to our guidelines we have to answer only…

Q: sec2 (을) dx 23

A: The given integral is ∫sec24x2x3dx.

Q: -sin(4x²) = dx

A:

Q: sin S S. cossx (3-2secs)

A: The given integral is ∫sin 5xcos2(5x)3-2sec(5x)dx The derivative formula is ddx(sec ax)=atan…

Q: 1³ csc x - sinx 5 sin x -dx

A:

Q: Solve 4 sin 2x S1₁= 8 4 -1 -¹x³ + x²-x² +2 dx

A:

Q: dx sech x (3 +5 sinh x)

A: Please see the explanation below.

Q: Q3) Solve for (y) if: In(y-2)= In(sinx)-x

A: As per our guidelines we are supposed to answer only one question. Kindly second question as the…

Q: dx (x – 2)Vx² – 4x +3 dx sin-1xV1- x2 L. cos(sec xVx2 – 1 -x) dx 2/V3

A:

Q: = In(x² + y- sin sin-1 a2.. ||

A:

Q: 3) Solve the equation sin(x) = ln(x) x1 = f(x) = f'(x) = X≈

A:

Q: 3- Sin4x dx S 3-Sin4x dx ノo

A:

Q: 2 S tan"(3x 1)sec (3x 1)dx - |

A:

Q: [s sec5 x tan4x dx

A:

Q: 2x+5 dx = AV7- 6x - x2 + B sin - (**)- 1. Vア-6xーx2 +C

A: ∫2x+57-6x-x2

Q: 4. tan'x seczx dx

A: To find: The integral of ∫tan7x·sec32xdx. Formula used: Power rule of integration: ∫xndx=xn+1n+1+C…

Q: csch (2 sin2x)dx 1. 1– 4x²

A:

Q: #4 tan lun sec x dx 4.

A:

Q: fx- sın (3-x) dx Sin.

A:

Q: Evaluate ∫ 3x2 sin(x3) dx.

A: To evaluate the integral  ∫3x2 sinx3 dx

Q: ) ㅠ S tan5 (2x) sec² (2x) dx 2

A:

Q: 1. 2. dx dx sin²(x² + 2x + 1) [4 tan(3x³) - 5 csc x]

A: To find derivatives

Q: 3 sinx 19. dx V1-x²

A:

Q: Evaluate : e2x sin3x dx

A: Introduction :

Q: sec(tan(2x)) – 4 6. dx (cos(2x))? 8. / e*-* dx T e3x-e3x

A:

Q: /x[cosh?(2x²) – sinh²(2x²) ]dx is equal to

A: solution :let…

Q: tan 2x dx 2. S (3+ln cos 2x)6

A:

Q: (cosh ' []] 1s dz

A:

Q: 8. Sxe* sin x² dx

A: We have to integrate .

Q: tanx * In(secx) dx

A:

Q: 4-S e²*sinx dx

A: We have to find the integration of the given function.

Q: Find Dx (sin4 x).

A: we have to find the value of Dxsin4x

Q: 1. D² {Sin ² x 3 2. JD²-15² √2e²x3

A: Here D is the differential operator. D=d/dx

Q: Solve sin 2x – dx x° +x* – x² +2 8

A: According to the given information, it is required to solve the given integral.

Q: Find 6x2 sin x3 dx

A:

Q: 3 y = sin³ 2x

A: We have to use chain rule here.

Q: #1. ( sin2r #2. rp- sinz 13. L #4.

A: To solve the given integrals we must know about the power rule of integration and trigonometric…

Q: dx sec5x(3+sin5х)

A:

Q: 5. S sinxtanx-cosxtanx dx sinxsecx(sinx+cosx)-5

A: Dear student, as per our rule we can only solve one question in one session. Please post the other…

Q: 2. S[ tanx- Secx]

A:

Q: 2 2- Find if y = dx sin2x sinx

A:

Q: (tan (3x)] = %3D dx A) 5 tan (3x) sec2 (3x). B) 15 tan (3x) sec2 (3x). c) 15 tan (3x) sec(3x). D) 5…

A: We have to find the derivative

Q: SOLVE: (y cosx +2xe")+(sinx +-ng'= 0 COS X

A:

Q: 5- y = 1+sin(4x2 + 2)

A: Note - As per our guidelines we will solve first question only and rest will reposted.  ddxxn =nxn-1…