(d) / VI- 40² dæ dt (e)/ Vt² -6t + 13 | Hint: If you complete the square, t2 – 6t + 13 = (t - 3)2 + 22. Use the substitution t- 3= 2 tan %3D

Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter8: Conic Sections
Section8.2: More Parabolas And Some Circles
Problem 63.1PS
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d and e please

2. Evaluate the following integrals using a suitable trigonometric substitution.
2V3
.3
(a) /vi
(a)
dx
V16 – x2
V1- 4x2 dx
-
dt
dt
(b)
t2 Vt2 – 16
(e) /
Vt2 – 6t + 13
Hint: If you complete the square,
t² – 6t + 13 = (t – 3)² + 2².
Use the substitution t - 3 = 2 tan
-
dx
Vx2 +16
-
Transcribed Image Text:2. Evaluate the following integrals using a suitable trigonometric substitution. 2V3 .3 (a) /vi (a) dx V16 – x2 V1- 4x2 dx - dt dt (b) t2 Vt2 – 16 (e) / Vt2 – 6t + 13 Hint: If you complete the square, t² – 6t + 13 = (t – 3)² + 2². Use the substitution t - 3 = 2 tan - dx Vx2 +16 -
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