Given two particles with Q = 2.90-μC charges as shown in the figure below and a particle with charge q = 1.32 x 10-18 C at the origin. (Note: Assume a reference level of potential V = 0 at r = ∞.)x= -0.800 myqO0 x = 0.800 mxQ(a) What is the net force (in N) exerted by the two 2.90-µC charges on the charge q? (Enter the magnitude.)0✓N(b) What is the electric field (in N/C) at the origin due to the two 2.90-μC particles? (Enter the magnitude.)0✔ N/C(c) What is the electrical potential (in kV) at the origin due to the two 2.90-μC particles?65.25kV(d) What If? What would be the change in electric potential energy (in J) of the system if the charge q were moved a distance d = 0.400 m closer to either of the 2.90-μC particles?1.14-10-13 X J

Answered: Image /qna-images/answer/499b60aa-5457-4306-b3e5-4736841c8ae9.jpg

Answered: (d) What If? What would be the change…

(d) What If? What would be the change in electric potential energy (in J) of the system if the charge q were moved a distance d = 0.400 m closer to either of the 2.90-µC particles? 1.14 10-13 X J

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter20: Electric Potential And Capacitance

Section: Chapter Questions

Problem 9P: Given two particles with 2.00-C charges as shown in Figure P20.9 and a particle with charge q = 1.28...

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