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TV sets: According to the Nielsen Company, the mean number of TV sets in a U.S. household in 2013 was 2.24. Assume the standard deviation is 1.2. A sample of 90 households is drawn. Part: 0/5 Part 1 of 5 (a) What is the probability that the sample mean number of TV sets is greater than 27 Round your answer to at least four decimal places. The probability that the sample mean number of TV sets is greater than 2 is Part: 1/5 Part 2 of 5 Part: 2/5 (b) What is the probability that the sample mean number of TV sets is between 2.5 and 3? Round your answer to at least four decimal places. The probability that the sample mean number of TV sets is between 2.5 and 3 is Part 3 of 5 The 70 percentile of the sample mean is Part: 3/5 Part 4 of 5 (c) Find the 70th percentile of the sample mean. Round your answer to at least two decimal places. It is not Part: 4/5 X X Part 5 of 5 $ S X (d) Would it be unusual for the sample mean to be less than 27 Round your answer to at least four decimal places. V unusual because the probability of the sample mean being less than 2 is $ X S (e) Can you tell whether it is unusual for an individual household to have fewer than 2 TV sets? It (Choose one) unusual because (Choose one)

TV sets: According to the Nielsen Company, the mean number of TV sets in a U.S. household in 2013 was 2.24. Assume the standard deviation is 1.2. A sample of 90 households is drawn. Part: 0/5 Part 1 of 5 (a) What is the probability that the sample mean number of TV sets is greater than 27 Round your answer to at least four decimal places. The probability that the sample mean number of TV sets is greater than 2 is Part: 1/5 Part 2 of 5 Part: 2/5 (b) What is the probability that the sample mean number of TV sets is between 2.5 and 3? Round your answer to at least four decimal places. The probability that the sample mean number of TV sets is between 2.5 and 3 is Part 3 of 5 The 70 percentile of the sample mean is Part: 3/5 Part 4 of 5 (c) Find the 70th percentile of the sample mean. Round your answer to at least two decimal places. It is not Part: 4/5 X X Part 5 of 5 $ S X (d) Would it be unusual for the sample mean to be less than 27 Round your answer to at least four decimal places. V unusual because the probability of the sample mean being less than 2 is $ X S (e) Can you tell whether it is unusual for an individual household to have fewer than 2 TV sets? It (Choose one) unusual because (Choose one)

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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TV sets: According to the Nielsen Company, the mean number of TV sets in a U.S. household in 2013 was 2.24. Assume the standard deviation is 1.2. A sample of 90 households is drawn. Part: 0 / 5 Part 1 of 5 (a) What is the probability that the sample mean number of TV sets is greater than 27 Round your answer to at least four decimal places. The probability that the sample mean number of TV sets is greater than 2 is Part: 1/5 - Part 2 of 5 Part: 2 / 5 (b) What is the probability that the sample mean number of TV sets is between 2.5 and 3? Round your answer to at least four decimal places. The probability that the sample mean number of TV sets is between 2.5 and 3 is Part 3 of 5 The percentile of the sample mean is Part: 3/5 (c) Find the 70th percentile of the sample mean. Round your answer to at least two decimal places. 70th Part 4 of 5 It is not Part: 4 / 5 X X Part 5 of 5 S 3 X (d) Would it be unusual for the sample mean to be less than 2? Round your answer to at least four decimal places. $ unusual because the probability of the sample mean being less than 2 is X S (e) Can you tell whether it is unusual for an individual household to have fewer than 2 TV sets? It (Choose one) unusual because (Choose one) X alo B
Transcribed Image Text:TV sets: According to the Nielsen Company, the mean number of TV sets in a U.S. household in 2013 was 2.24. Assume the standard deviation is 1.2. A sample of 90 households is drawn. Part: 0 / 5 Part 1 of 5 (a) What is the probability that the sample mean number of TV sets is greater than 27 Round your answer to at least four decimal places. The probability that the sample mean number of TV sets is greater than 2 is Part: 1/5 - Part 2 of 5 Part: 2 / 5 (b) What is the probability that the sample mean number of TV sets is between 2.5 and 3? Round your answer to at least four decimal places. The probability that the sample mean number of TV sets is between 2.5 and 3 is Part 3 of 5 The percentile of the sample mean is Part: 3/5 (c) Find the 70th percentile of the sample mean. Round your answer to at least two decimal places. 70th Part 4 of 5 It is not Part: 4 / 5 X X Part 5 of 5 S 3 X (d) Would it be unusual for the sample mean to be less than 2? Round your answer to at least four decimal places. $ unusual because the probability of the sample mean being less than 2 is X S (e) Can you tell whether it is unusual for an individual household to have fewer than 2 TV sets? It (Choose one) unusual because (Choose one) X alo B
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W Part 4 of 5 (d) Would it be unusual for the sample mean to be less than 27 Round your answer to at least four decimal places. ▼ unusual because the probability of the sample mean being less than 2 is It is not is Part: 4/5 Part 5 of 5 X (e) Can you tell whether it is unusual for an individual household to have fewer than 2 TV sets? It (Choose one) unusual because (Choose one) X 3 F Submit Assignment 2022 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center Accessibility
Transcribed Image Text:W Part 4 of 5 (d) Would it be unusual for the sample mean to be less than 27 Round your answer to at least four decimal places. ▼ unusual because the probability of the sample mean being less than 2 is It is not is Part: 4/5 Part 5 of 5 X (e) Can you tell whether it is unusual for an individual household to have fewer than 2 TV sets? It (Choose one) unusual because (Choose one) X 3 F Submit Assignment 2022 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center Accessibility
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