Data & Results: Complete the table. TRIAL 1 TRIAL 2 TRIAL 3 Wt. of vinegar sample Vol. of vinegar sample 8.2000 g 8.1000 g 8.2500 g 10.00 ml 10.00 ml 10.00 ml Titration Data Final Reading 24.30 mL 24.00 mL 24.40 ml Initial Reading 0.00 ml 0.00 mL 0.00 ml Total vol. of NAOH used Ave.Std. Concn. of NaOH, (N) 24.30 mL 24.00 mL 24.40 ml % CH;COOH Ave. % CH;COH

Appl Of Ms Excel In Analytical Chemistry
2nd Edition
ISBN:9781285686691
Author:Crouch
Publisher:Crouch
Chapter2: Basic Statistical Analysis With Excel
Section: Chapter Questions
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Data & Results:  Complete the table.

 

Eq. Wt CH;COOH= MM CH;COOH = 60 g/mol = 60 g/eg
(n=1 replaceable H)
1
1 eq/mol
To compute for %CH;COOH:
N N2OH x VN2OH x Eq.Wt. CH:COOH x 100%
Wt. of sample
%CH;COOH =
Transcribed Image Text:Eq. Wt CH;COOH= MM CH;COOH = 60 g/mol = 60 g/eg (n=1 replaceable H) 1 1 eq/mol To compute for %CH;COOH: N N2OH x VN2OH x Eq.Wt. CH:COOH x 100% Wt. of sample %CH;COOH =
The following data were obtained by a group of students in Analytical Chem.
Data & Results: Complete the table.
TRIAL 1
TRIAL 2
TRIAL 3
Wt. of vinegar sample
Vol. of vinegar sample
8.2000 g
8.1000 g
8.2500 g
10.00 ml
10.00 ml
10.00 ml
Titration Data
Final Reading
Initial Reading
Total vol. of NAOH used
Ave.Std. Concn. of NaOH, (N)
24.30 ml
24.00 ml
24.40 mL
0.00 ml
0.00 ml
0.00 ml
24.30 ml
24.00 mL
24.40 mL
% CH;COOH
Ave. % CH;COOH
Transcribed Image Text:The following data were obtained by a group of students in Analytical Chem. Data & Results: Complete the table. TRIAL 1 TRIAL 2 TRIAL 3 Wt. of vinegar sample Vol. of vinegar sample 8.2000 g 8.1000 g 8.2500 g 10.00 ml 10.00 ml 10.00 ml Titration Data Final Reading Initial Reading Total vol. of NAOH used Ave.Std. Concn. of NaOH, (N) 24.30 ml 24.00 ml 24.40 mL 0.00 ml 0.00 ml 0.00 ml 24.30 ml 24.00 mL 24.40 mL % CH;COOH Ave. % CH;COOH
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