Data for a power plant shown in Figure 3 are also provided in Table 3 below. The plant operates on a regenerative vapor power cycle with four feedwater heaters, three closed and one open, and reheat. Steam enters the turbine at 16,000 kPa, 600°C, expands in three stages to the reheat pressure of 2000 kPa, is reheated to 500°C, and then expands in three more stages to the condenser pressure of 10 kPa. Saturated liquid exits the condenser at 10 kPa. Between the first and second stages, some steam is diverted to a closed feedwater heater at 8000 kPa. Between the second and third stages, additional steam is diverted to a second closed feedwater heater at 4000 kPa. Steam is extracted between the fourth and fifth turbine stages at 800 kPa and fed into an open feedwater heater operating at that pressure. Saturated liquid at 800 kPa leaves the open feedwater heater. Between the fifth and sixth stages, some steam is diverted to a closed feedwater heater at 200 kPa. Condensate leaves each closed feedwater heater as saturated liquid at the respective extraction pressures. Consider isentropic processes in each turbine stage and adiabatic processes in the pumps, all closed feedwater heaters, all traps, and the open feedwater heater. a. Illustrate the cycle in the TS diagram and

Elements Of Electromagnetics
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Please give only the ts diagram

8. Data for a power plant shown in Figure 3 are also provided in Table 3 below. The plant operates on a
regenerative vapor power cycle with four feedwater heaters, three closed and one open, and reheat. Steam
enters the turbine at 16,000 kPa, 600°C, expands in three stages to the reheat pressure of 2000 kPa, is reheated
to 500°C, and then expands in three more stages to the condenser pressure of 10 kPa. Saturated liquid exits
the condenser at 10 kPa. Between the first and second stages, some steam is diverted to a closed feedwater
heater at 8000 kPa. Between the second and third stages, additional steam is diverted to a second closed
feedwater heater at 4000 kPa. Steam is extracted between the fourth and fifth turbine stages at 800 kPa and
fed into an open feedwater heater operating at that pressure. Saturated liquid at 800 kPa leaves the open
feedwater heater. Between the fifth and sixth stages, some steam is diverted to a closed feedwater heater at
200 kPa. Condensate leaves each closed feedwater heater as saturated liquid at the respective extraction
pressures. Consider isentropic processes in each turbine stage and adiabatic processes in the pumps, all closed
feedwater heaters, all traps, and the open feedwater heater.
a. Illustrate the cycle in the TS diagram and
b.
Show that
Seam
generaler
21-
Closed
15
16
L"
b.1 the fraction of the steam diverted between the first and second stages is 0.1000
b.2 the fraction of the steam diverted between the second and third stages is 0.1500
the fraction of the steam diverted between the fourth and fifth stages is 0.0009.
the fraction of the steam diverted between the fifth and sixth stages is 0.1302.
b.3
b.4
Cloned
bouter
17
18
Deserating
open
beater
Main boric
feed pump
19
Caned
W₁
Condenser
10
Figure 3. Schematic Diagram for Problem 8
8
20
-Condensate
party
State
1234567
8
9
10
11
12
13
14
15
16
17
18
19
20
21
Table 3. Data for Problem 8
p (kPa) T(C) h (kJ/kg) s (kJ/kg-K)
16,000 600
8,000
4,000
2,000
2,000 500
800
200
10
10
800
800
800
16,000
16,000
8,000
4,000
4,000
800
200
10
16,000
3573.5
3334.7
3129.2
2953.6
3467.6
3172.1
2824.7
2355.4
191.83
192.63
595.92
721.11
738.05
1067.3
1316.6
1316.6
1087.3
1087.3
504.70
504.70
1269.1
6.6399
6.6399
6.6399
6.6399
7.4317
7.4317
7.4317
7.4317
0.6493
0.6517
1.7553
2.0462
2.0837
2.7584
3.2068
3.2344
2.7964
2.8716
1.5301
1.6304
3.1245
0.9042
.0
0
0.1338
0
0.1788
0
0.1308
Transcribed Image Text:8. Data for a power plant shown in Figure 3 are also provided in Table 3 below. The plant operates on a regenerative vapor power cycle with four feedwater heaters, three closed and one open, and reheat. Steam enters the turbine at 16,000 kPa, 600°C, expands in three stages to the reheat pressure of 2000 kPa, is reheated to 500°C, and then expands in three more stages to the condenser pressure of 10 kPa. Saturated liquid exits the condenser at 10 kPa. Between the first and second stages, some steam is diverted to a closed feedwater heater at 8000 kPa. Between the second and third stages, additional steam is diverted to a second closed feedwater heater at 4000 kPa. Steam is extracted between the fourth and fifth turbine stages at 800 kPa and fed into an open feedwater heater operating at that pressure. Saturated liquid at 800 kPa leaves the open feedwater heater. Between the fifth and sixth stages, some steam is diverted to a closed feedwater heater at 200 kPa. Condensate leaves each closed feedwater heater as saturated liquid at the respective extraction pressures. Consider isentropic processes in each turbine stage and adiabatic processes in the pumps, all closed feedwater heaters, all traps, and the open feedwater heater. a. Illustrate the cycle in the TS diagram and b. Show that Seam generaler 21- Closed 15 16 L" b.1 the fraction of the steam diverted between the first and second stages is 0.1000 b.2 the fraction of the steam diverted between the second and third stages is 0.1500 the fraction of the steam diverted between the fourth and fifth stages is 0.0009. the fraction of the steam diverted between the fifth and sixth stages is 0.1302. b.3 b.4 Cloned bouter 17 18 Deserating open beater Main boric feed pump 19 Caned W₁ Condenser 10 Figure 3. Schematic Diagram for Problem 8 8 20 -Condensate party State 1234567 8 9 10 11 12 13 14 15 16 17 18 19 20 21 Table 3. Data for Problem 8 p (kPa) T(C) h (kJ/kg) s (kJ/kg-K) 16,000 600 8,000 4,000 2,000 2,000 500 800 200 10 10 800 800 800 16,000 16,000 8,000 4,000 4,000 800 200 10 16,000 3573.5 3334.7 3129.2 2953.6 3467.6 3172.1 2824.7 2355.4 191.83 192.63 595.92 721.11 738.05 1067.3 1316.6 1316.6 1087.3 1087.3 504.70 504.70 1269.1 6.6399 6.6399 6.6399 6.6399 7.4317 7.4317 7.4317 7.4317 0.6493 0.6517 1.7553 2.0462 2.0837 2.7584 3.2068 3.2344 2.7964 2.8716 1.5301 1.6304 3.1245 0.9042 .0 0 0.1338 0 0.1788 0 0.1308
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