Data: (Remember to write correct units!!) 1st Type of Metal: Aluminnum I52.5g 10.19 Mass of Water (in calorimeter) 42.14 27°C 2nd Type of Metal:CORPER 71.2g 10:1g Mass of Water (in calorimeter)69.19 27°C ऽ४°८ . Mass of Cups & Water Mass of Cups & Water Mass of Cups Mass of Cups Initial Temp. of Water Use for #1 below Initial Temp. of Water *Final Temp of Water *Final Temp of Water 91g 33° Use for #2 88°0 1:89 32°C Mass of metal Mass of metal Initial Temp. Hot Metal Initial Temp. Hot Metal below *Final Temp. Metal (in calorimeter) *Final Temp. Metal (in calorimeter) *= same temp. Results: 1. Calculate the heat gained by the water (lost by the substance) in the calorimeter using the equation in the Introduction. Remember to write the units!! Q for water using 2nd Metal Q for water using 1st Metal Qwater = mwater X (Tf-Ti)water X Cp w Qwater = mwater x (Tf-Ti)water x Cp water water 2. Calculate the specific heat of the substance using the answer from number 1 and the equation in the Introduction. Now, Cp is your unknown since you're using Q from #1. Cp for 2nd Metal Cp of 1st Metal Qsubst = msubst x (Ti-Tf)subat x Cp su Qsubst Qsubst = mgubst x (Ti-Tf)subst x Cp Qsubst subst subst Cp = Cp = mubat X (Ti-Tf) subst mubst X (Tj-Tf) sut subst Cp = Jig- C Cp = J/g - C 3 sf 3 sf

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Chapter5: Temperature And Heat
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Specific Heat Lab
Data: (Remember to write correct units!!)
1st Type of Metal: Aluminnum
2nd Type of Metal: CORper
152.5g
10.19
Mass of Water (in calorimeter) 2.14
27°C
Mass of Cups & Water
79.29
10.1g
Mass of Cups & Water
Mass of Cups
Mass of Cups
I69,1g
27°C
ऽ४°८.
Mass of Water (in calorimeter)
Initial Temp. of Water
Use for #1
Initial Temp. of Water
below
*Final Temp of Water
*Final Temp of Water
919
27:89
32°C
Mass of metal
Mass of metal
33¢ Use for #2
below
Initial Temp. Hot Metal
Initial Temp. Hot Metal
88°0
*Final Temp. Metal
(in calorimeter)
*Final Temp. Metal
(in calorimeter)
* = same temp.
Results:
1. Calculate the heat gained by the water (lost by the substance) in the calorimeter using the equation
in the Introduction. Remember to write the units!!
Q for water using 1st Metal
Q for water using 2nd Metal
Qwater = mwater x (Tf-Ti)water Xx Cp
water
Qwater = mwater X (Tf- Ti)water X Cp
water
2. Calculate the specific heat of the substance using the answer from number 1 and the equation in
the Introduction. Now, Cp is your unknown since you're using Q from #1.
Cp for 2nd Metal
Cp of 1st Metal
Qsubst = msubst X (Ti-Tf) subst X Cp subst
Qsubst
%3D
Qsubst = msubst X (Tj- Tf)subat X Cp
Qsubst
%3D
subst
1sqns
Cp
%3D
maubat X (Ti- If) subst
maubst X (Ti- If) subst
Cp =
J/g - C
Cp =
Jlg - C
3 sf
3 sf
3. Look up the specific heat of your substance samples and find your percent error.
Substance # 2: Experimental Cp
Substance #1: Experimental Cp
Substance #2: Literature Cp
Substance #1: Literature Cp
|
Percent Yield:
Percent Yield:
Transcribed Image Text:Specific Heat Lab Data: (Remember to write correct units!!) 1st Type of Metal: Aluminnum 2nd Type of Metal: CORper 152.5g 10.19 Mass of Water (in calorimeter) 2.14 27°C Mass of Cups & Water 79.29 10.1g Mass of Cups & Water Mass of Cups Mass of Cups I69,1g 27°C ऽ४°८. Mass of Water (in calorimeter) Initial Temp. of Water Use for #1 Initial Temp. of Water below *Final Temp of Water *Final Temp of Water 919 27:89 32°C Mass of metal Mass of metal 33¢ Use for #2 below Initial Temp. Hot Metal Initial Temp. Hot Metal 88°0 *Final Temp. Metal (in calorimeter) *Final Temp. Metal (in calorimeter) * = same temp. Results: 1. Calculate the heat gained by the water (lost by the substance) in the calorimeter using the equation in the Introduction. Remember to write the units!! Q for water using 1st Metal Q for water using 2nd Metal Qwater = mwater x (Tf-Ti)water Xx Cp water Qwater = mwater X (Tf- Ti)water X Cp water 2. Calculate the specific heat of the substance using the answer from number 1 and the equation in the Introduction. Now, Cp is your unknown since you're using Q from #1. Cp for 2nd Metal Cp of 1st Metal Qsubst = msubst X (Ti-Tf) subst X Cp subst Qsubst %3D Qsubst = msubst X (Tj- Tf)subat X Cp Qsubst %3D subst 1sqns Cp %3D maubat X (Ti- If) subst maubst X (Ti- If) subst Cp = J/g - C Cp = Jlg - C 3 sf 3 sf 3. Look up the specific heat of your substance samples and find your percent error. Substance # 2: Experimental Cp Substance #1: Experimental Cp Substance #2: Literature Cp Substance #1: Literature Cp | Percent Yield: Percent Yield:
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