de (10%) Problem 7: A 3-D printer lays down a semicircular arc of positively charged plastic with a radius R=2.9 cm, and a linear charge density of λ = +1.8 µC/m. After the printer has finished the arc, the stylus moves to the center of the arc as shown. The minute segment of the plastic arc highlighted in the diagram subtends an angle de. Note the measurement of the angle 0 shown in the figure. Stylus tip y R X Otheexpertta.com ✓ 14% Part (a) Input a symbolic expression for the charge dq on the segment of charge of size de in terms of given parameters. dq=λR de ✔ Correct! 14% Part (b) Input a symbolic expression for the electric force vector, exerted by the minute segment of plastic subtending the arc de on an electron (charge -e), within the stylus at the center of the arc. Express your answer in terms of given parameters, fundamental constants, and the unit vectors i and j in the specified coordinate system. dF=ke λ d0/R X Attempts Remain Feedback: is available. A 14% Part (c) Find the indefinite integral of the x-component Fx from part (b), but do not evaluate the limits. ✓ 14% Part (d) Select the limits of integration that would result in the correct calculation of the force exerted by the entire line of plastic on an electron in the stylus as shown in the diagram. 0-/2 to 07/2✔ Correct! 14% Part (e) Using the limits from part (d) and the expression from part (c) to determine an expression for the magnitude of the electrical force exerted by the positively charged line of plastic on the electron in the stylus. F = 2 kλe/R ✔✓ Correct! 14% Part (f) Calculate the magnitude of the electric force, in newtons, exerted by the positively charged line of plastic on the electron in the stylus. F=2.8 * 10-17 F = 2.8E-17 X Attempts Remain ▷ A 14% Part (g) What direction is the electric force exerted on the electron in the stylus? Ө
de (10%) Problem 7: A 3-D printer lays down a semicircular arc of positively charged plastic with a radius R=2.9 cm, and a linear charge density of λ = +1.8 µC/m. After the printer has finished the arc, the stylus moves to the center of the arc as shown. The minute segment of the plastic arc highlighted in the diagram subtends an angle de. Note the measurement of the angle 0 shown in the figure. Stylus tip y R X Otheexpertta.com ✓ 14% Part (a) Input a symbolic expression for the charge dq on the segment of charge of size de in terms of given parameters. dq=λR de ✔ Correct! 14% Part (b) Input a symbolic expression for the electric force vector, exerted by the minute segment of plastic subtending the arc de on an electron (charge -e), within the stylus at the center of the arc. Express your answer in terms of given parameters, fundamental constants, and the unit vectors i and j in the specified coordinate system. dF=ke λ d0/R X Attempts Remain Feedback: is available. A 14% Part (c) Find the indefinite integral of the x-component Fx from part (b), but do not evaluate the limits. ✓ 14% Part (d) Select the limits of integration that would result in the correct calculation of the force exerted by the entire line of plastic on an electron in the stylus as shown in the diagram. 0-/2 to 07/2✔ Correct! 14% Part (e) Using the limits from part (d) and the expression from part (c) to determine an expression for the magnitude of the electrical force exerted by the positively charged line of plastic on the electron in the stylus. F = 2 kλe/R ✔✓ Correct! 14% Part (f) Calculate the magnitude of the electric force, in newtons, exerted by the positively charged line of plastic on the electron in the stylus. F=2.8 * 10-17 F = 2.8E-17 X Attempts Remain ▷ A 14% Part (g) What direction is the electric force exerted on the electron in the stylus? Ө
College Physics
1st Edition
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:Paul Peter Urone, Roger Hinrichs
Chapter18: Electric Charge And Electric Field
Section: Chapter Questions
Problem 9CQ: Figure 18.43 shows the charge distribution in a water molecule, which is called a polar molecule...
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please help with B,C,F,G
Transcribed Image Text:(10%) Problem 7: A 3-D printer lays down a semicircular arc of positively charged plastic
with a radius R = 2.9 cm, and a linear charge density of λ = +1.8 µC/m. After the printer has
finished the arc, the stylus moves to the center of the arc as shown. The minute segment of the
plastic arc highlighted in the diagram subtends an angle de. Note the measurement of the angle 0
de
shown in the figure.
Stylus tip
y
R
X
Otheexpertta.com
✓ 14% Part (a) Input a symbolic expression for the charge dq on the segment of charge of size de in terms of given parameters.
dq=λR de ✔ Correct!
14% Part (b) Input a symbolic expression for the electric force vector, exerted by the minute segment of plastic subtending the arc de on an electron
(charge -e), within the stylus at the center of the arc. Express your answer in terms of given parameters, fundamental constants, and the unit vectors i and j in
the specified coordinate system.
dF = ke λ d0/R X Attempts Remain
Feedback: is available.
A 14% Part (c) Find the indefinite integral of the x-component Fx from part (b), but do not evaluate the limits.
✓ 14% Part (d) Select the limits of integration that would result in the correct calculation of the force exerted by the entire line of plastic on an electron in
the stylus as shown in the diagram.
0= π/2 to 0= x/2 ✓ Correct!
14% Part (e) Using the limits from part (d) and the expression from part (c) to determine an expression for the magnitude of the electrical force exerted
by the positively charged line of plastic on the electron in the stylus.
F = 2 kλe/R ✓ Correct!
14% Part (f) Calculate the magnitude of the electric force, in newtons, exerted by the positively charged line of plastic on the electron in the stylus.
F=2.8 * 10-17
F = 2.8E-17 X Attempts Remain
▷ A 14% Part (g) What direction is the electric force exerted on the electron in the stylus?
D
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