de Evaluate: J æ/9a2 + 4 A f (x) = 9x2 + 4 + 2 In +C 3x (B f (x) = -2 ln V9x2 + 4 + 2 +C 3x © f (x) 9x²+ 4+2 In +C 3x (D f (x) = -4 ln V9x2 + 4 + 2 +C 3x None of the given choices
de Evaluate: J æ/9a2 + 4 A f (x) = 9x2 + 4 + 2 In +C 3x (B f (x) = -2 ln V9x2 + 4 + 2 +C 3x © f (x) 9x²+ 4+2 In +C 3x (D f (x) = -4 ln V9x2 + 4 + 2 +C 3x None of the given choices
Elementary Geometry for College Students
6th Edition
ISBN:9781285195698
Author:Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:Daniel C. Alexander, Geralyn M. Koeberlein
Chapter6: Circles
Section6.CT: Test
Problem 11CT: aIf HP=4, PJ=5, and PM=2, find LP. _ bIf HP=x+1, PJ=x1, LP=8, and PM=3, find x. _
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Question
Transcribed Image Text:dx
Evaluate:
LEV9² + 4
f (x) = - In
V9x2 + 4 + 2
+ C
3x
B
f (x) = -2 ln
9x2 +4 +2
+C
3x
© f(x) = -
V9x2 + 4 + 2
In
+C
3x
V9x2 +4 + 2
+C
D
f (x) = -4 ln
E) None of the given choices
dz
if we let y= z+4, then the new integral becomes
In
Vz+4 - 2
у-2
A) True
B) False
x² + 64
Using trigonometric substitution, given -
dx, the simplified form of the integral is:
( sec ede
tan?e
True
B) False
[Vx²-25
dx is x2 - 25 - sec-lx+ C.
The antiderivative of
A) True
B False
In
dx , we let x= 5sine.
A) True
B False
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