Deduce the identity of the following compound from the spectral data given. C8H10: 1H NMR, 6 1.20 (3H, triplet), 2.60 (2H, quartet), 7.12 (5H, singlet) (ppm); IR, 3050, 2970, 1600 cm-1; MS, m/z 91
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Q: Propose a structure for D (molecular formula C9H9ClO2) consistent with the given spectroscopic data.…
A: Given: The molecular formula of the given compound is C9H9ClO2.
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Q: An unknown compound has the molecular formula C6H12O2. The compound shows a strong peak in its IR…
A: molecular formula C6 H12 O2 IR Spectrum - 1700 this peak is due to C=O stretching
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Q: Assume a compound with the formula C4H8O. a) How many double bonds and/or rings does your compound…
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Q: Propose a structure for each of the following two isomers with formula C6H14 given their 1H-NMR…
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Q: Thymol (molecular formula C10H14O) is the major component of the oil of thyme. Thymol shows IR…
A: Given information: Molecular formula for thymol = C10H14O Absorption peak at 3500-3200, 3150-2850,…
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Q: 8. (6) Deduce the identity of the following compound from the TH NMR data given and IR data. C6H8O4:…
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- Thymol (molecular formula C10H14O) is the major component of the oil ofthyme. Thymol shows IR absorptions at 3500–3200, 3150–2850, 1621, and1585 cm−1. The 1H NMR spectrum of thymol is given below. Propose apossible structure for thymol.Compound A, C8H10O, has the IR and 1H NMR spectra shown. Propose a structure consistent with the observed spectra, and label each peak in the NMR spectrum. Note that the absorption at 5.5 î disappears when D2O is added.Compound C has molecular formula C5H8O. The IR, mass, 1H-NMR, and 13C-NMR spectra are shown below. Suggest a structure for C and explain your reasoning.
- Phenacetin is an analgesic compound having molecular formula C10H13NO2. Once a common component in over-thecounter pain relievers such as APC (aspirin, phenacetin, caffeine), phenacetin is no longer used because of its liver toxicity. Deduce the structure of phenacetin from its 1H NMR and IR spectra.Compounds B and C are isomers with molecular formula C5H9BrO2. The 1H NMR spectrum of compounds B and C are shown below. The IR spectrum corresponding to compound B showed strong absorption bands at 1739, 1225, and 1158 cm-1, while the spectrum corresponding to compound C have strong bands at 1735, 1237, and 1182 cm-1. 1.Based on the information provided, determine the structure of compounds B and C. 2.Assign all peaks in 1H NMR spectrum of compounds B and C.Following are 1H-NMR spectra for compounds B (C6H12O2) and C (C6H10O). Upon warming in dilute acid, compound B is converted to compound C. Deduce the structural formulas for compounds B and C.
- Assume a compound with the formula C4H8O. a) How many double bonds and/or rings does your compound contain? b) If your compound shows an infrared absorption peak at 1715 cm-1, what functional group does it have? c) If your compound shows a single 1H NMR absorption peak at 2.1 δ, what is its structure?Propose a structure for a compound of molecular formula C7H14O2 with an IR absorption at 1740 cm−1 and the following 1H NMR data:Identify the structures of D and E, isomers of molecular formulaC6H12O2, from their IR and 1H NMR data. Signals at 1.35 and 1.60 ppm inthe 1H NMR spectrum of D and 1.90 ppm in the 1H NMR spectrum of Eare multiplets.
- A solution of acetone [(CH3)2C=O] in ethanol (CH3CH2OH) in the presence of a trace of acid was allowed to stand for several days, and a new compound of molecular formula C7H16O2 was formed. The IR spectrum showed only one major peak in the functional group region around 3000 cm−1, and the 1H NMR spectrum is given here. What is the structure of the product?γ-Butyrolactone (C4H6O2, GBL) is a biologically inactive compound that is converted to the biologically active recreational drug GHB (Section 19.5) by a lactonase enzyme in the body. Since γ-butyrolactone is more fat soluble than GHB, it is more readily absorbed by tissues and thus produces a faster onset of physiological symptoms. γ-Butyrolactone shows an absorption in its IR spectrum at 1770 cm−1 and the following 1H NMR spectral data: 2.28 (multiplet, 2 H), 2.48 (triplet, 2 H), and 4.35 (triplet, 2 H) ppm. What is the structure of γ-butyrolactone?Compound X (molecular formula C10H12O) was treated with NH2NH2,−OH to yield compound Y (molecular formula C10H14). Based on the 1H NMR spectra of X and Y given below, what are the structures of X and Y?