Derive an equation for determining the density of a floating/wooden object using Archimedes’ Principal without knowing the volume of the object(s). Your answer should be in terms of the mass of the wood un-submerged, the density of water, Reading 1 or m1, and reading 2 or m2 from the procedure above. Include a free body diagram.

Physics for Scientists and Engineers, Technology Update (No access codes included)
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Chapter14: Fluid Mechanics
Section: Chapter Questions
Problem 14.3OQ: A wooden block floats in water, and a steel object is attached to the bottom of the block by a...
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2. Derive an equation for determining the density of a floating/wooden object using Archimedes’ Principal without knowing the volume of the object(s). Your answer should be in terms of the mass of the wood un-submerged, the density of water, Reading 1 or m1, and reading 2 or m2 from the procedure above. Include a free body diagram.

Answer: Pw=(Pf)Mw/M2-M1

3. Finally, derive an equation using Archimedes’ Principal showing how the density of a liquid can be measured. Your expression should be in terms of the density of water, the object’s buoyant force mass in NaCl solution, and the object’s buoyant force mass in water (i.e. in terms of the quantities in Table 1). No free-body diagram is needed.

Answer: Pnacl=(Pwater)Mb,nacl/Mb,water

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