Derive the following identity (an easier way to compute SSE): - SSE = Syy - B₁Say, where Syy = (Y₁ – Ý)² and Sxy = Σ²±1(xi − ˜)(Yi — Ý). - -
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- Prove that bx=exln(b) for positive b1 .Suppose w=x/y+y/z, where x=e^(4t), y=2+sin(4t), and z=2+cos(3t). A ) Use the chain rule to find dw/dt as a function of x, y, z, and t. Do not rewrite x, y, and z in terms of t, and do not rewrite e^(4t) as x. dw/dt=? B ) Use part A to evaluate dw/dt when t=0.For which values of a does x + a = 0 have a solution in Z5?
