Derive the thermal efficiency of a heat engine from the 1st law of thermodynamics. Since the process is cyclic, then AU = 0 so: =W Since: Q = QH+QC = |QH|-|QC| Then W = But the efficiency e= /QH Thus e = ) =

Derive the thermal efficiency of a heat engine from the 1st law of thermodynamics. Since the process is cyclic, then AU = 0 so: =W Since: Q = QH+QC = |QH|-|QC| Then W = But the efficiency e= /QH Thus e = ) =

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

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Question

100%

Derive the thermal efficiency of a heat engine from the 1st law of thermodynamics.
Since the process is cyclic, then AU = 0
so:
=W
Since:
Q = QH+QC = |QH|-|QC|
Then
W =
But the efficiency
e=
/QH
Thus
e =
+(
- |

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