Design a bearing type bolt connection to transmit a dead load of 200kips and live load of 280kips, by using two channels C10×30 having gross area of 8.812sq in and thickness of 0.873 inch. Use A36 bolts having Fn 60ksi, Fu = 55Ksi and diameter = 0.85inch. A 0.75inch gusset plate and resistance factor of %3D 0.75 should be used.

Design a bearing type bolt connection to transmit a dead load of 200kips and live load of 280kips, by using two channels C10×30 having gross area of 8.812sq in and thickness of 0.873 inch. Use A36 bolts having Fn 60ksi, Fu = 55Ksi and diameter = 0.85inch. A 0.75inch gusset plate and resistance factor of %3D 0.75 should be used.

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter3: Tension Members

Section: Chapter Questions

Problem 3.6.6P: Use load and resistance factor design and select a W shape with a nominal depth of 10 inches (a W...

See similar textbooks

Similar questions

The riveted lap connection shown consists of two(2) – PL 12 mm × 280 mm. 1. If allowable bearing stress in holes is 1.2Fu where Fu is the ultimate strength of the plate and which is equal to 400 MPa, find the maximum allowable force P that can be applied neglecting effect of eccentricity. a. 563.3 kN b. 460.8 kN c. 683. 6 kN d. 405.9 kN 2. If allowable yielding of gross area is Fy/1.67, where Fy is the yield strength of the plate and which is equal to 250 MPa, find the maximum allowable force P that can be applied neglecting effect of eccentricity. a. 534 kN b. 560 kN c. 446 kN d. 503 kN 3. If diameter of hole equals diameter of rivet, what is the net area of edge-3-4-edge in square millimeters? a. 2540 b. 2590 c. 2880 d. 2040
Design a weld connection for an UNP 280×80×9 of S 355 (fy= 355 MPa and fu= 470MPa) steel connected to a 10 mm gusset plate. The guesst plate is S275. Please draw all calculated values on a sketch with full dimensions. D= 335 KNL= 670 KN
The bracket connection shown in Figure must support an eccentric load consisting of 9 kips of dead load and 27 kips of live load. The connection was designed to have two vertical rows of four bolts, but one bolt was inadvertently omitted. If 7⁄8inchdiameter Group A bearingtype bolts are used, is the connection adequate? Assume that the bolt threads are in the plane of shear. Use A36 steel for the bracket, A992 steel for the W6 x 25, and perform the following analyses: (a) elastic analysis, (b) ultimate strength analysis.
The plate shown is attached by using three M12x2 grade 8.8 bolts. Which screw is subjected to the largest stress? What safe load ( static) F can be supported by the screw for n=1.5.
Design a weld connection for an UNP 280×80×9 of S 355 (fy= 355 MPa and fu= 470MPa) steel connected to a 10 mm gusset plate. The guesst plate is S275. Please draw all calculated values on a sketch with full dimensions.
Give me right solution Select a single angle member to resist a tensile load of 60 kN dead plus 40 kN live. The member is 2.5m long and is assumed to be connected with one row of 20 mm ∅ bolts.
Two steel plate tension members have been connected using 0.72 inch diameter bolts arranged in an equally-spaced 9 by 3 rectangular formation. Both plates have a thickness equal to 1/3 in. Take shear fracture stress as 51.2 ksi, clear distance for each edge bolt as 0.12 in, and the clear distance for the other bolts as 1.072 in. a)Sketch the connection showing all the details and measurements with units. b)Find the maximum allowable service dead load and live load assuming live load is half as much as dead load. Consider ASD.
9) what is the weld capacity of the shear connection in kips? (2 decimal places) A992: Fy=50ksi, Fu=65ksiA36: Fy=36ksi, Fu=58ksieffective bolt hole diameter = bolt hole + 1/16"beam properties: tw=0.38 in., bf=7.07 in., tf=0.63 in.Fexx=70ksi
i) what is the weld capacity of the shear connection in kips? (2 decimal places)A992: Fy=50ksi, Fu=65ksiA36: Fy=36ksi, Fu=58ksieffective bolt hole diameter = bolt hole + 1/16"beam properties: tw=0.38 in., bf=7.07 in., tf=0.63 in.Fexx=70ksi
Calculate the capacity of the shear connection below. A36 Plate: Fyp= 248MPa, Fup= 400MPa. A992 Beam; Fyb= 345MPa, Fub= 450MPa. Fexx= 480MPa. twb= 10.92mm tp= 12, X= 45, nr= 3(no. of bolts) What is the bolt shear capacity in kN? What is the bearing capacity of the shear plate in kN? What us the bearing capacity of the beam in kN? What is the shear yielding capacity of shear plate in kN? What is the shear rupture capacity of the shear plate in kN? What is the block shear rupture capacity of shear plate in kN? What is the weld capacity in kN?
A plate 3⁄8 3 6 is used as a tension member to resist a service dead load of 12 kips and a service live load of 33 kips. This member will be connected to a 3⁄8-inch gusset plate with 3⁄4-inch-diameter Group A bolts. A36 steel is used for both the tension member and the gusset plate. Assume that the bearing strength is adequate, and determine the number of bolts required based on bolt shear.
A bracket must support the service loads shown in the figure below. The loads act through the center of gravity of the connection. The connection to the column flange is with eight 7/8-inch diameter, A325N bolts. A992 steel is used for all components. Is the connection adequate? Use LRFD. Show all work to verify the bearing strength and the combined effects from tension and shear in the bolts. Ignore any potential prying action created in the WT.