determine back the missing data on blank lines
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- Bearing Angle Traverse Given the tabulated measurement of the closed traverse as shown. Determine the missing data. Line Length Bearing AB 589.060 m N 87°30’ E BC 291.860 m N 30°30’ E CD 656.980 m S 42°45’ E DE 654.060 m Unknown EF 686.660 m Unknown FA 391.730 m N 07°02’ E Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES. please answer this with accuracy and with proven solution. thank you.Bearing Angle Traverse Given the tabulated measurement of the closed traverse as shown. Determine the missing data. Line Length Bearing AB 249.180 m S 19°32’ E BC Unknown N 74°09’ E CD 445.100 m S 36°40’ E DE 668.270 m S 51°14’ W EF 866.790 m N 73°25’ W FG Unknown N 26°00’ W GA 560.150 m N 64°32’ E Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES. kindly provide an accurate and detailed solution. thank you so much.Calculate the probable error (mean) 545.789 545.180 544.988 545.543
- Course Bearing Length Interior Angle (Right) AB S 50°54'23'' E 329.722 m A = 120°07'10'' BC 210.345 m B = 59°39'10'' CD 279.330 m C = 248°00'57'' DE 283.426 m D = 86°51'04'' EF 433.007 m E = 102°09'16'' FA 307.625 m F = 103°12'41'' Compute and tabulate for the following closed-polygon traverse: (a) preliminary bearings (b) unadjusted departures and latitudes (c) linear misclosure and (d) relative precision. (Note: line BC bears NE.) If one side and/or angle is responsible for most of the error of closure, which is it likely to be?Bearing Angle Traverse Given the tabulated measurement of the closed traverse as shown. Determine the Area of the Traverse. Line Length Bearing AB 589.060 m N 87°30’ E BC 391.730 m N 07°02’ E CD 291.860 m N 30°30’ E DE 656.980 m S 42°45’ E EF 654.060 m Unknown FA 686.660 m Unknown Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES.Bearing Angle Traverse Given the tabulated measurement of the closed traverse as shown. Determine the missing data. Line Length Bearing AB 413.600 m N 09°30’ W BC 304.380 m N 55°06’ W CD 407.210 m S 57°35’ W DE Unknown S 04°05’ E EA 649.630 m Unknown Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES.
- Convert the following distances given in survey feet to meters:(a) 537.52 sft (b) 504,864.39 sft (c) 3874.26 sftGeometric space, i need solutions in 15 minutes please. MCQ/ If Ø = 0.987643 rad. Find Ø in degrees. A-56º 35' 16'' B-45º 42' 16'' C-52º 04' 26'' D-54º 30' 16'' E-35º 25' 25'' F-65º 25' 13''Bearing Angle Traverse Given the tabulated measurement of a closed traverse with unknown length and bearing of line EA, determine the following: The Latitude and Departure of each Line. The Length of Line EA. The Bearing of Line EA. Plot the Traverse. Line Length Bearing AB 585.730 m S 47°10’ E BC 496.080 m N 65°38’ E CD 999.900 m S 79°52’ E DE 795.340 m N 55°25’ E EA Unknown Unknown Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES. Note: Please be accurate in providing solution. Thank you so much.
- Azimuth Traverse Given the tabulated measurement of a closed traverse with unknown length and azimuth of line DE, determine the following: The Latitude and Departure of each Line. The Length of Line DE. The Azimuth of Line DE. The Bearing of each Line. Plot the Traverse. Line Length Azimuth from North AB 453.730 m 112°06’ BC 486.080 m 178°50’ CD 398.270 m 290°30’ DE Unknown Unknown EA 400.150 m 75°42’ Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES.Azimuth Traverse Given the tabulated measurement of a closed traverse with unknown length and azimuth of line DE, determine the following: The Latitude and Departure of each Line. The Length of Line DE. The Azimuth of Line DE. The Bearing of each Line. Plot the Traverse. Line Length Azimuth from North AB 453.730 m 112°06’ BC 486.080 m 178°50’ CD 398.270 m 290°30’ DE Unknown Unknown EA 400.150 m 75°42’ Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES. please provide a proven and accurate solution. thank you.Question 16 The interior angles of a hexagon were observed and recorded as follows: A= 122 deg 31’02”, B= 123 deg 26’17”, C=130 deg 05’07”, D=120 deg 15’7”, E= 160 deg 50’35” and F= 62 deg 53’07”. The discrepancy of the measurement is Choose here A = 1’30” B= 0’30” C= 2’30” D=1’00” E=2’50” F= 1’15”