Determine the change in the volume of the cylinder of the refrigerant-134a if the specific volume and enthalpy of R-134a at the initial state of 90.4 kPa and -10°C and at the final state of 90.4 kPa and 15°C are as follows: n = 0.2418 m3/kg, hm = 247.77 kJ/kg v2 = 0.2670 m3/kg, and h2 = 268.18 kJ/kg

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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A piston-cylinder device contains 0.91 kg of refrigerant-134a at –10°C. The piston that is free to move has a mass of 12 kg
and a diameter of 25 cm. The local atmospheric pressure is 88 kPa. Now, heat is transferred to refrigerant-134a until the
temperature is 15°C. Use data from the tables.
R-134a
-10°C
Problem 03.030.b - Change of volume of cylinder with refrigerant
Determine the change in the volume of the cylinder of the refrigerant-134a if the specific volume and enthalpy of R-134a at the initial
state of 90.4 kPa and -10°C and at the final state of 90.4 kPa and 15°C are as follows:
1= 0.2418 m3/kg, m = 247.77 kJ/kg
v2 = 0.2670 m3/kg, and h2 = 268.18 kJ/kg
The change in the volume of the cylinder is
]m³.
Transcribed Image Text:A piston-cylinder device contains 0.91 kg of refrigerant-134a at –10°C. The piston that is free to move has a mass of 12 kg and a diameter of 25 cm. The local atmospheric pressure is 88 kPa. Now, heat is transferred to refrigerant-134a until the temperature is 15°C. Use data from the tables. R-134a -10°C Problem 03.030.b - Change of volume of cylinder with refrigerant Determine the change in the volume of the cylinder of the refrigerant-134a if the specific volume and enthalpy of R-134a at the initial state of 90.4 kPa and -10°C and at the final state of 90.4 kPa and 15°C are as follows: 1= 0.2418 m3/kg, m = 247.77 kJ/kg v2 = 0.2670 m3/kg, and h2 = 268.18 kJ/kg The change in the volume of the cylinder is ]m³.
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