An agency uses the following formula to determine pavement condition rating,PCR = 99.3 − 5.51 (5.0-ROUGH) − 1.59 LNALL − 0.221 AVGOUT − 0.0306 LONG − 0.531 TRAN,where we have the following.ROUGH = roughness measured by present serviceability rating (PSR), scale of 0 to 5 LNALL = natural logarithm of alligator cracking, ft per mile AVGOUT = outer wheel path rutting (all locations averaged), 0.01 inch LONG = longitudinal cracking, ft per mile TRAN = transverse cracking, number of cracks per mileAnd, present serviceability rating is determined as the following.PSR = 5e−0.0051118 · IRI − 0.0016027A pavement section has the following distress data.IRI = 108 in./mi Alligator cracking = 110 ft/mi Average rutting = 0.20 in. Longitudinal cracks = 130 ft/mi Transverse cracks = 12/miDetermine the current PCR for this section.PCR =Now, assume a new roughness measurement is expected soon. When PCR falls below 60, the section will be scheduled for rehabilitation. Determine the new IRI value (in in./mi) that will trigger the rehabilitation. An agency uses the following formula to determine pavement condition rating,PCR = 99.3 - 5.51 (5.0-ROUGH) - 1.59 LNALL - 0.221 AVGOUT -0.0306 LONG - 0.531 TRAN,where we have the following.ROUGH = roughness measured by present serviceability rating (PSR), scale of 0 to 5LNALL = natural logarithm of alligator cracking, ft per mileAVGOUT = outer wheel path rutting (all locations averaged), 0.01 inchLONG = longitudinal cracking, ft per mileTRAN =transverse cracking, number of cracks per mileAnd, present serviceability rating is determined as the following.PSR = 5e-0.0051118 IRI - 0.0016027A pavement section has the following distress data.IRI = 108 in./miAlligator cracking = 110 ft/miAverage rutting = 0.20 in.Longitudinal cracks = 130 ft/miTransverse cracks = 12/miDetermine the current PCR for this section.PCR =Now, assume a new roughness measurement is expected soon. When PCR falls below 60, the section will be scheduled forrehabilitation. Determine the new IRI value (in in./mi) that will trigger the rehabilitation.in./mi

Answered: Determine the current PCR for this…

Traffic and Highway Engineering

5th Edition

ISBN:9781305156241

Author:Garber, Nicholas J.

Publisher:Garber, Nicholas J.

Chapter19: Design Of Flexible Highway Pavements

Section: Chapter Questions

Problem 13P: Repeat Problem 19-7 using two different depths of untreated aggregate bases of 6 in. and 12 in....

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An agency uses the following formula to determine pavement condition rating,

PCR = 99.3 − 5.51 (5.0-ROUGH) − 1.59 LNALL − 0.221 AVGOUT − 0.0306 LONG − 0.531 TRAN,

where we have the following.

ROUGH = roughness measured by present serviceability rating (PSR), scale of 0 to 5 LNALL = natural logarithm of alligator cracking, ft per mile AVGOUT = outer wheel path rutting (all locations averaged), 0.01 inch LONG = longitudinal cracking, ft per mile TRAN = transverse cracking, number of cracks per mile

And, present serviceability rating is determined as the following.

PSR = 5e^{−0.0051118 · IRI − 0.0016027}

A pavement section has the following distress data.

IRI = 108 in./mi Alligator cracking = 110 ft/mi Average rutting = 0.20 in. Longitudinal cracks = 130 ft/mi Transverse cracks = 12/mi

Determine the current PCR for this section.

PCR =

Now, assume a new roughness measurement is expected soon. When PCR falls below 60, the section will be scheduled for rehabilitation. Determine the new IRI value (in in./mi) that will trigger the rehabilitation.

An agency uses the following formula to determine pavement condition rating,
PCR = 99.3 - 5.51 (5.0-ROUGH) - 1.59 LNALL - 0.221 AVGOUT -0.0306 LONG - 0.531 TRAN,
where we have the following.
ROUGH = roughness measured by present serviceability rating (PSR), scale of 0 to 5
LNALL = natural logarithm of alligator cracking, ft per mile
AVGOUT = outer wheel path rutting (all locations averaged), 0.01 inch
LONG = longitudinal cracking, ft per mile
TRAN =
transverse cracking, number of cracks per mile
And, present serviceability rating is determined as the following.
PSR = 5e-0.0051118 IRI - 0.0016027
A pavement section has the following distress data.
IRI = 108 in./mi
Alligator cracking = 110 ft/mi
Average rutting = 0.20 in.
Longitudinal cracks = 130 ft/mi
Transverse cracks = 12/mi
Determine the current PCR for this section.
PCR =
Now, assume a new roughness measurement is expected soon. When PCR falls below 60, the section will be scheduled for
rehabilitation. Determine the new IRI value (in in./mi) that will trigger the rehabilitation.
in./mi

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Determine the current PCR for this section. PCR Now, assume a new roughness measurement is expected soon. When PCR falls below 60, the section will be scheduled for rehabilitation. Determine the new IRI value (in in./mi) that will trigger the rehabilitation. in./mi