I don’t know how to account for the brakes and chute for the deceleration. Question 4 of 4View PoliciesAnswer: s= iCurrent Attempt in ProgressThe 242000-lb space-shuttle orbiter touches down at about 229 mi/hr. The drag chute is deployed at 183 mi/hr, the wheel brakes areapplied at 82 mi/hr until wheelstop, and the drag chute is jettisoned at 29 mi/hr. If the drag chúte results in a deceleration of-0.000180v² (in feet per second squared when the speed v is in feet per second) and the wheel brakes cause a constant deceleration of5.5 ft/sec², determine the distance s traveled from 183 mi/hr to wheelstop.eTextbook and MediaSave for Later<AUG316>ftW-/1 E :Attempts: 0 of 2 used Submit Answer3,052tv

a = -0.000180 va = -5.5 ft/s2a = -5.5 ft/s2mass m = 242000 lb

Answered: determine the distance s traveled from…

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determine the distance s traveled from 183 mi/hr to wheelstop.

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter7: Dry Friction

Section: Chapter Questions

Problem 7.11P: Solve Prob. 7.10 assuming that the pick-up truck has front-wheel drive.

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