Determine the forces in members AC and AD of the truss. D 4 kN 6 m ! |4 m 2 m E +2.5 m→l B 5 m
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Determine the forces in members AC and AD of the truss shown below.
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- Find the support reacions and joint force of the construction shown on the figure, if; P=12 kN q=9 kN/m M=12 kN and L=2 mThe simplest truss consists of two rods and is loaded by the block. Given: block weight Q = 9,4 kN. Angle α = 31 degrees. Find: the algebraic (positive or negative) value (in kN) of normal force N1 in the rod 1, considering that N1>0 for tension and N1<0 for compression.please is urgent The 7.8m steel I-beam has a mass of 800kg and is lifted into position by applying a force P on the trolley to which the lower end B is secured. Cable AC is tied center of the beam and is horizontal when B is exactly below C. Determine, in function of x, the force P needed to maintain equilibrium from x=0 to the value of x at which A' lies exactly below C. Find the maximum value of P and the corresponding value of x.
- Determine the tensions T1 and T2 in the strings required to maintain equilibrium for the suspended object weighs W = 48.7N shown in the figure. Take, α = 29.4° & β = 47.5°. a) The value of θ1 (Degree) = b) The value of θ2 (Degree) = c) The value of θ3 (Degree) = d) The value of Tension, T1 (N) = e) The value of Tension, T2 (N) =Determine Reaction and Internal Member ForcesCompute the magnitudes of all forces acting on member CDE of the frame. answer: Pbc= 10.0 kips, Pbd= 20.0 kips, E= 19.70 kips
- The simplest truss consists of two rods and is loaded by the force F. Given: F = 5,1 kN. Angle α = 69 degrees. Find: the algebraic (positive or negative) value (in kN) of normal force N1 in the rod 1, considering that N1>0 for tension and N1<0 for compression.SITUATION 7: Three forces P1, P2, and P3 are acting on a semi-circular structure as shown in Fig. THA-33. Support at A is hinge and support at B is roller. Given: a = 1 m; P1 = 1.8 kN; P2 = 0.9 kN; P3 = 0.45 kN; θ = 30⁰; β = 45⁰. Calculate the resultant of the three forces (in kN). (Answer: 2.45) Calculate the vertical reaction at B (kN). (Answer: 1.06) Calculate the reaction at A. (Answer: 1.63)Use the Section Method to find member forces EA, BE, and CB. P = 4 kN
- Question 3) The position of the head and neck and the forces acting on the head are shown in the figure. The center of gravity of the head of mass m=8 kg is located at point C. The joint reaction force of FJ=147 N, which makes an angle of α= 42° with the vertical from the point B, is acting on the skull by the neck extensor muscles. The center of the atlantooccipital joint is located at point B. For this flexion position of the head, FM neck muscle force, which makes an angle of γ with the horizontal from the A point, is effective. (Take the gravitational acceleration g as 9.81 m/s2). Accordingly; a) Calculate the angle γ of the FM muscle strength with the horizontal. b) Calculate the FM muscle strength. (Write your result in N.) AnswerA rear suspension system for a front wheel-drive vehicle is shown here. Spring EF is offset behind member CD. The normal force due to contact between the wheel and the road is 4200 N. Assume the weight of the wheel and suspension system components is negligible. Determine the magnitude of the member CD. Is the member in tension or compression? Determine the support reactions at A. Determine the unstretched length of the spring EF given a spring constant of 150 kN/m.For the rigid frame shown in figures, determine:a) the nodal displacements and rotations of the nodes b) the reaction c) the forces in each element