QUESTION 13Determine the Kh for CN at 25°C. The K, for HCN is 4.9 x 10 -10O 2.3 x 10-9O 3.7 x 10-7O 4.9 x 10-14O 1.4 x 10-5O 2.0 x 10-5

Answered: Image /qna-images/answer/c286410f-3a77-4f49-8a50-0cae5a8a5222.jpg

Answered: Determine the K, for CN at 25°C. The K…

Science

Chemistry

Determine the K, for CN at 25°C. The K for HCN is 4.9 x 10 10 O 2.3 x 10-9

Chemistry: An Atoms First Approach

2nd Edition

ISBN:9781305079243

Author:Steven S. Zumdahl, Susan A. Zumdahl

Publisher:Steven S. Zumdahl, Susan A. Zumdahl

Chapter17: Electrochemistry

Section: Chapter Questions

Problem 89E

See similar textbooks

Related questions

Q: Using the data in our Coursebook: Calculate ΔG° and K (at 298) for this reaction: 2H2S(g) + SO2(g)↔…

Q: Using any data you can find in the ALEKS Data resource, calculate the equilibrium constant K at 25.0…

A: The equilibrium constant of a chemical reaction is the value of its reaction quotient at chemical…

Q: Use the chart to answer the question: At what temperature is the reaction at standard conditions…

A: When the system is at equilibrium, neither products nor reactants will be favored at this stage.At…

Q: For the reaction 2NO(g) + O2(g)2NO2(g) H° = -114.2 kJ and S° = -146.5 J/K The equilibrium…

Q: Calculate the value of K, for the equation C(s) + CO, (g) =2CO(g) Kp = ? given that at a certain…

A: Given: C(s)+2H2O(g)⇋CO2(g)+2H2(g) KP1=3.51H2(g)+CO2(g)⇋H2O(g)+CO(g) KP2=0.759 To find: Overall…

Q: Determine K for a reaction at 200 K if AG° =24.6 kJ/mol. (R = 8.314 J/mol · K)

A: Given Temperature ( T ) = 200K Standard Gibbs free energy ( ∆G° ) = 24.6 KJ/mol…

Q: Determine K for a reaction at 200 K if AG° =22.7 kJ/mol. (R = 8.314 J/ mol · K)

A: Can find answer in the image below

Q: Determine K for a reaction at 200 K if AG° =22.8 kJ/mol. (R = 8.314 J/mol · K)

A: Given is ΔG° = 22.8 kJ/mol = 22800 J/mol T = 298 K R = 8.314 J/mol-K We are to find the equilibrium…

Q: Determine K for a reaction at 200 K if ∆G° =11.6 kJ/mol. (R = 8.314 J/mol ･ K)

A: The relation between the standard Gibbs free energy change and the equilibrium constant is as…

Q: How can we calculate an Equilibrium Constant from ∆G?

A: ∆G is Gibbs free energy change ∆G= - RT logn K under standard conditions ∆G0=-2.303 RT log10 K or…

Q: Determine K for a reaction at 200 K if AG° =15.1 kJ/mol. (R = 8.314 J/mol · K)

A: Given :- ∆G° = 15.1 kJ/mol R = 8.314 J/mol.K T = 200 K To determine :- Value of K

Q: For a certain chemical reaction, the standard Gibbs free energy of reaction at 5.00 °C is 56.8 kJ.…

A: Given∆G° = 56.8 kJ = 56800 JTemperature = T = 5.00° CT = (5+273.15) K = 278.15 KR = gas constant =…

Q: Determine K for a reaction at 200 K if ∆G° =22.7 kJ/mol. (R = 8.314 J/mol ･ K)

A: Interpretation: The value of K for a reaction at 200 K is to be determined.

Q: The equilibrium constant, K, for the following reaction is 1.29x10 at 600 K. Calculate K, for this…

Q: Consider the following reaction: Cl2(g) + PCI3(g) + PCI5(g) Kc = 453 at 100°C %3D Calculate K, for…

Q: For the reaction N2(g) + 3H2(g)–→2NH3(g) AH° = -92.2 kJ and AS° =-198.7 J/K The equilibrium constant…

A: The formula that relates the Gibbs free energy change (ΔG°) to the equilibrium constant(K) of a…

Q: For the reaction 2 NOCl (g) à 2 NO (g) + Cl2 (g) KP is 1.4 x 101 at 550°C. Calculate KC for the…

A: We will solve this question using relation between Kp and Kc.

Q: Determine K for a reaction a 200 K if AG° =19.3 kJ/mol. (R = 8.314 J/mol K)

A: The value of K can be found using a relation that relates the equilibrium constant (K) and free…

Q: Determine K for a reaction at 200 Kif AG° =26.4 kJ/mol. (R = 8.314 J/mol · K)

Q: The equilibrium constant, Kc, for the following reaction is 6.50x10-3 at 298 K. Calculate K, for…

Q: Determine K for a reaction at 200 K if ∆G° =12.5 kJ/mol. (R = 8.314 J/mol ･ K)

A: Given data, T = 200 K R = 8.314 J/mol.K ∆G° =12.5 kJ/mol = 12.5 × 103 J By using the following…

Q: The equilibrium constant, K, for a neutralization reaction can be symbolized as Kn- Determine K, at…

A: The question is based on the concept of chemical equilibrium. we have to calculate equilibrium…

Q: For the equilibrium N2O4 ⇌ ⇌ 2 NO2 ? α is 0.05 at 298 K and 1 atm. Calculate K

A: Given equilibrium is N2O4 ⇌ 2 NO2 Initial pressure is 1 atm Degree of dissociation , α = 0.05…

Q: What is K for a reaction if ∆G° =173.2 kJ/mol at 25.0 °C? (R = 8.314 J/mol ･ K)

A: Given, Standard gibbs free energy (∆G°) = 173.2 kJ/mol = 173.2 × 1000 J/mol = 173200 J/mol…

Q: 3. For the following calculate either K, if Ke is given or calculate Ke if Kp is given. Use a…

A: As you have asked subparts (a) and (b) of question 3, we will solve the same for you. 3 (a) I2 (g)…

Q: When a AH>0 and TAS<0 the reaction will be: а. spontaneous O b. system is an equilibrium С. not…

A: The reaction will be not spontaneous if Delta G > 0 And in this question we have to tell that…

Q: Determine K for a reaction at 200 K if ∆G° =16.7 kJ/mol. (R = 8.314 J/mol ･ K)

Q: Gibbs Free Energy, G (kJ) On the graph, label the equilibrium composition of the system with an А.…

A: For this energy profile diagram , each point represents a particular thing. In this diagram, curve…

Q: What is K for a reaction if AG° =-218.2 kJ/mol at 25°C? (R = 8.314 J/mol · K)

A: ∆G° = -RTlnk ∆G° = Standard free energy change R = universal gas constant T = temperature K =…

Q: For the reaction N2(g) + 20,(g)→2NO,(g) AH° = 66.4 kJ and AS° =-121.6 J/K The equilibrium constant…

A: The reaction given is, => N2 (g) + 2 O2 (g) --------> 2 NO2 (g) Given : ΔHo = 66.4 KJ = 66400…

Q: For the reaction NH4NO3(aq)N2O(g) + 2H2O(l) H° = -149.6 kJ and S° = 99.9 J/K The equilibrium…

A: Spontaneous processes are those processes which take place on their own without providing any energy…

Q: AG° at 298 K for this reaction is -33.3 kJ/mol. The value of AG at 298 K for a reaction mixture that…

A: Introduction The value of Delta G can be calculated by applying the following expression Delta G =…

Q: For the reaction 2NO(g) + 02(g)- →2NO2(g) AH° = -114.2 kJ and AS° = -146.5 J/K The equilibrium…

A: Given, ΔH0 = - 114.2 kJ = - 114200 J ΔS0 = - 146.5 J/K T = 350.0 K ΔG0 = ΔH0 - TΔS0…

Q: For the reaction 4HCI(g) + O2(g) 2H,0(g) + 2Cl2(g) AH° = -114.4 kJ and AS° = -128.9 J/K The…

Q: Multiple Choice.

Q: Determine K for a reaction at 200 K if ∆G° =24.4 kJ/mol. (R = 8.314 J/mol ･ K)

Q: Use the values given in Appendix L in your textbook to calculate K. for the reaction between…

Q: Calculate the value of K, for the equation C(s) + CO, (g) =2CO(g) Kp = given that at a certain…

Q: Calculate K, for H,0(g) + K0, (g)=H,0,(g) using the following data: H,(g) +0,(g) H,0,(g) K, = 2.3 x…

Q: Calculate K given Ecell= -0.210 volts E0cell= -0.140 volts T= 483 Kelvin n= 1 R= 8.314 J/mol K…

A: To solve this problem we will use the Nernst Equation to get the value of K

Q: Be sure to answer all parts. Using the data in the table, calculate Kp and AGfor this reaction at…

A: For a general reaction aA + bB → cc + dD…

Q: For the reaction NH4NO3(aq)N2O(g) + 2H2O(l) H° = -149.6 kJ and S° = 99.9 J/K The equilibrium…

A: The relationship between the change in free energy (∆G°), change in enthalpy (∆H°) is furnished as…

Q: Calculate the value at K. for the hypothetical reaction: Q(g)+2X(g) = M(g)

Q: 20.56 Calculate K at 298 K for each reaction: (a) NO(g) + 0,(g) (b) 2HCI(g) = H;(g) + Cl,(g) (c)…

A: Equilibrium constant can be denoted by symbol K.

Q: b Calculate K (at 298 K) for this reaction. K =

Q: Calculate K, for the following reaction: PCI3 (3) + Cl2 (3) PCI5 K = 1.67 (at 500K)

A: Kp = Kc (RT)∆n Where, ∆n = moles of gaseous products - moles of gaseous reactants T = temperature in…

Q: Determine the temperature of a reaction if K = 1.20 x 10-6 when AG° = +39.40 kJ/mol.

A: Given data is as follows: The equilibrium constant (K) = 1.20×10-6 The value of standard gibbs…

Question

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions

17. Which one of the changes given below will cause the equilibrium posi:on to shid to the led for the following reversible chemical reac:on? 4NH3(g) + 3O2(g) ←-------→ 2N2(g) + 6H2O(g) + Heat a. Adding more ammonia b. Decreasing the temperature c. Adding a catalyst d. increasing the concentra:on of oxygen e. Increasing the pressure by decreasing the volume
Calculate T (in K) given ΔG^0= -19.4 kJ/mol and ΔH^0= 69.9 kJ/mol and ΔS^0= 253 J/mol KΔG^0=ΔH^0−TΔS^0 A) 706 B) 1,760 C) 353 D) 0.353 E) 118
What is K for a reaction if ∆G° =-364.8 kJ/mol at 25.0 °C? (R = 8.314 J/mol ･ K)
In the reaction 450.0⁰c: caco3(s) ⇌ cao(s) + co2(g), at equilibrium, if pco2 = 0.0160 atm , what is the value of Kc
Question 2:For reaction 2 A(aq) <---> B(aq) + C(aq), the change in standard free enthalpy is 1.33 kJ at 25oC. The initial concentration of A is 0.572 M, the initial concentration of B is 0.347 M, and the initial concentration of C is 0.221 M. At equilibrium (still at 25oC), what will be the concentration of A(aq) (in mol/L)?
Incorrect is shown in red. Not sure how to calculate the equilibrium constant Kc
Consider the following equilibrium: N2O4(g) ⇄2NO2(g). If Kp = 0.144 at 950.0 K, calculate Kc. (no scientific notation)
The Ka for HClO is 3.0 x 10-8. Calculate [H+] at equilibrium if the initial [HClO] = 0.075M.
If Kp = 563 for the reaction below at 310 K, then what is the value of Kc? 2 A (g) + B (s) ⇌ 2 C (s) + D (g) A 1.20 L weather balloon on the ground has a temperature of 25.0°C and is at atmospheric pressure (1.00 atm). When it rises to an elevation where the pressure is 0.760 atm, then the new volume is 1.80 L. What is the temperature (in °C) of the air at this elevation? If 72.6 grams of carbonic acid are sealed in a 2.00 L soda bottle at room temperature (298.15 K) and decompose completely via the equation below, what would be the final pressure of carbon dioxide (in atm) assuming it had the full 2.00 L in which to expand? H₂CO₃(aq) → H₂O(l) + CO₂(g) Avogadro's Law explores the relationship between volume and number of moles of an ideal gas. Avogadro's Law is described as V₁/n₁ = V₂/n₂. Assume you have 2.00 moles of a gas with an initial volume of 2.30 L. Another 2.00 moles of gas were added to the container. Calculate the final volume of the gas in the container in L. What is the…
Using the information from appendix G, calculate the value of K for the following equilibrium at 25oC. O2(g) + O(g) ⇆ O3(g)
Ka of HNO2 in 25 degree is 4.5 x 10^-4. (a) Write the equilibrium chemical reaction corresponding to Ka for nitrous acid (HNO2) at 25°C. (b) Calculate ΔG° for the dissociation of nitrous acid in solution using the given Ka value. (c) What is the value of ΔG at equilibrium? (d) When [H+] = 5.0 × 10^-2 M, [NO2^-] = 6.0 × 10^-4 M, [HNO2] = 0.20 M, what is the value of ΔG?
Phosphoric acid has a formula of H3PO4 , and has a Ka1 of 7.5×10–3 , Ka2 of 6.2×10–8 , and Ka3 of4.2×10–13 at 25 ºC. What is the equilibrium constant for the following reaction at 25°C?HPO42– (aq) + H2O(l) -> H2PO4– (aq) + OH– (aq)