Determine the KVAR rating of the capacitor connected in each phase. Also comment on the type of supplied KVAR, Whether it is unity, leading or lagging.
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A 3-Φ, 5 KW induction motor has a p.f of 0.75 lagging. A bank of capacitors is connected in delta across the supply terminals and p.f raised to 0.9 lagging. Determine the KVAR rating of the capacitor connected in each phase. Also comment on the type of supplied KVAR, Whether it is unity, leading or lagging.
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- A source supplies power to the following three loads connected in parallel: (1) a lighting load drawing 10kW. (2) an induction motor drawing 10kVA at 0.90 power factor lagging, and (3) a synchronous motor operating at 10hp,85 effIciency and 0.95 power factor leading (1hp=0.746kW). Determine the real, reactive, and apparent power delivered by the source. Also, draw the source power triangle.An industrial plant consisting primarily of induction motor loads absorbs 500 kW at 0.6 power factor lagging. (a) Compute the required kVA rating of a shunt capacitor to improve the power factor to 0.9 lagging. (b) Calculate the resulting power factor if a synchronous motor rated at 500 hp with 90 efficiency operating at rated load and at unity power factor is added to the plant instead of the capacitor. Assume constant voltage (1hp=0.746kW).Figure 2.26 shows three loads connected in parallel across a 1000-V(RMS),60Hz single-phase source. Load 1: Inductive load, 125kVA,0.28PF lagging. Load 2: Capacitive load, 10kW,40kvar. Load 3: Resistive load, 15kW. (a) Determine the total kW, kvar, kva, and supply power factor. (b) In order to improve the power factor to 0.8 lagging. a capacitor of negligible resistance is connected in parallel with the above loads. Find the kvar rating of that capacitor and the capacitance in F. Comment on the magnitude of the supply current after adding the capacitor.
- A load of 500 kVA operates on 1100 V, 50 Hz mains with power factor of 0.6 lagging. It is required to improve the power factor to 0.95 lagging by using the star connected capacitor bank. Assuming that the load KVA remains constant, suggest the rating of the capacitors.The total kVA rating of capacitors required to raise the full-load power factor of a 3-phase, 440 V, 50 Hz induction motor from 0.75 to 0.85 lagging is Qc = 15 KVAR. Capacitors are delta connected. (i) Determine the line current drawn by the capacitor bank (ii) Determine the phase current of the capacitor bank (iii) Determine the capacitive reactance per phase Xc (iv) What will be the capacitance per phase if the capacitors are delta connected ?An industrial plant consists of several induction motors. The plant absorbs 300 kW at 0.6 PF lagging from the substation bus. Compute the required kVAR rating of the capacitor connected across the load toraise the power factor to 0.9 lagging. A 200-hp, 90% efficiency, synchronous motor is operated from the same busat rated conditions and 0.8 power factor leading. Calculate the resulting powerfactor.
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- A 25 kVA, 240 V single phase source supply the rated power at the rated voltage to a motor at 0.8 power factor lagging. Find the capacitor bank in order to improve the power factor to 0.9 lagging connected to a motor.a. Calculate the real power, reactive power and current before capacitor bank is connected? b. Calculate the power and reactive power after capacitor bank is connected? c.What is kVA rating of capacitor bank QC?Q4: A 50 Hz, 11KV, 3-ph, alternator with earthed neutral has a reactance of 5 Ω\ ph and is connected to bus bar through a C.B. The distributed capacitance up to C.B between phase and neutral is 0.01μF, determine: 1-the recovery voltage across the contacts of the breaker, 2-the frequency of oscillation, 3- The restriking voltage across the contacts of the breaker, 4-the average rate of rise of restriking voltage up to the first peak, 5- the time to reach the peak restriking voltage, 6- the value of resistance to be used across the contacts of C.B. to eliminate the restriking voltage, and 7- the value of inductance and capacitance of this systemA 3 phase, 50-Hz, star-connected, 2,00 kVA, 2,300-V alternator gives a short-circuit current of 600A for a certain field excitation. With the same excitation, the O.C. voltage was 900V. The resistance between a pair of terminals was 0.12 Ω. Find the full-load regulation at (a) unity p.f., (b) 0.85 p.f. lagging, (c) 0.85 p.f. leading.