This subject is strength of materialsshow complete and clear solution with free body diagram and pressure diagramDONT SHORTCUT THE SOLUTION THANK YOU Determine the Poisson's ratioV. *Determine the decrease in the4.05-in. cross-sectionaldimension (in inches). * 88% 7:52. A steel bar, whose cross section is0.55 inch by 4.05 inches, was testedin tension. An axial load of P = 31,000Ib. produced a deformation of 0.105inch over a gauge length of 2.05inches and a decrease of 0.0075 inchin the 0.55-inch thickness of the bar.Determine the lateral strain. *Determine the axial strain. *

GIVEN- width= 0.55 in height= 4.05 in P= 31000

Answered: Determine the lateral strain.

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Mechanical Engineering

Determine the lateral strain.

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter1: Tension, Compression, And Shear

Section: Chapter Questions

Problem 1.6.7P: A wine of length L = 4 ft and diameter d = 0.125 in. is stretched by tensile forces P = 600 lb. The...

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Thermal Properties of Materials

In mechanical engineering, the thermal property is represented as the physical quantity that is relevant to the application of heat. The thermal properties are evaluated by variations in any specific material due to low heat or high heat. The quantities that influence the thermal property of the materials are mass, density, temperature, and many others.

Question

This subject is strength of materials

show complete and clear solution with free body diagram and pressure diagram

DONT SHORTCUT THE SOLUTION THANK YOU

Determine the Poisson's ratio
V. *
Determine the decrease in the
4.05-in. cross-sectional
dimension (in inches). *

88% 7:5
2. A steel bar, whose cross section is
0.55 inch by 4.05 inches, was tested
in tension. An axial load of P = 31,000
Ib. produced a deformation of 0.105
inch over a gauge length of 2.05
inches and a decrease of 0.0075 inch
in the 0.55-inch thickness of the bar.
Determine the lateral strain. *
Determine the axial strain. *

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