Determine the moles of AICI, produced when 4.75 grams of Cl₂ reacts with Al according to the following reaction: 2 Al(s) + 3 Cl₂(g) → 2 STARTING AMOUNT X AICI 3(S)

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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter3: Stoichiometry
Section: Chapter Questions
Problem 130E: Hexamethylenediamine (C6H16N2) is one of the starting materials for the production of nylon. It can...
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Determine the moles of AICI, produced when 4.75
grams of Cl₂ reacts with Al according to the following
reaction:
STARTING AMOUNT
ADD FACTOR
x( )
X
70.91
0.0894
0.0994
26.98
1
2 Al(s) + 3 Cl₂(g) → 2 AICI3(s)
4.75
2
3
0.101
133.34
0.0447
X
ANSWER
=
g AICI 3
mol AICI 3
mol Cl₂
mol Al
g/mol Al
g Al
g Cl₂
g/mol AICI 3
RESET
3
g/mol Cl₂
Transcribed Image Text:Determine the moles of AICI, produced when 4.75 grams of Cl₂ reacts with Al according to the following reaction: STARTING AMOUNT ADD FACTOR x( ) X 70.91 0.0894 0.0994 26.98 1 2 Al(s) + 3 Cl₂(g) → 2 AICI3(s) 4.75 2 3 0.101 133.34 0.0447 X ANSWER = g AICI 3 mol AICI 3 mol Cl₂ mol Al g/mol Al g Al g Cl₂ g/mol AICI 3 RESET 3 g/mol Cl₂
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