Determine the resultant of the concurrent forces in KN below. F1 = 222 KN, 01 = 59° F2 = 689 KN, 02 = 68°, F3 = 482 kN, 03 = 26°. Write numerical value only with 2 decimal places LL 0₁ 03 میرا +Y F₂ Fy + X

Principles of Foundation Engineering (MindTap Course List)
8th Edition
ISBN:9781305081550
Author:Braja M. Das
Publisher:Braja M. Das
Chapter6: Vertical Stress Increase In Soil
Section: Chapter Questions
Problem 6.4P: Refer to Figure P6.4. A strip load of q = 900 lb/ft2 is applied over a width B = 36 ft. Determine...
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Determine the resultant of the concurrent forces in KN below. F1 = 222
KN, 01 = 59° F2 = 689 KN, 02 = 68°, F3 = 482 kN, 03 = 26°. Write
numerical value only with 2 decimal places
0₁
Fx
03
e
!+ Y
82
1+Y
F₂
A Force of F = 224 lb is directed in the figure with 8 = 28 degrees.
Determine the y component of the force in lb. Input only the numerical
value with 2 decimal places.
Fy
+ X
+ X
Transcribed Image Text:Determine the resultant of the concurrent forces in KN below. F1 = 222 KN, 01 = 59° F2 = 689 KN, 02 = 68°, F3 = 482 kN, 03 = 26°. Write numerical value only with 2 decimal places 0₁ Fx 03 e !+ Y 82 1+Y F₂ A Force of F = 224 lb is directed in the figure with 8 = 28 degrees. Determine the y component of the force in lb. Input only the numerical value with 2 decimal places. Fy + X + X
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