Determine the resulting pH when 0.003 mol of solid NaOH is added to a 100.0 mL buffer containing 0.13 M HClO and 0.37 M NaClO. The value of Ka for HClO is 2.9 × 10⁻⁸

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Chapter14: Acids And Bases
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Determine the resulting pH when 0.003 mol of solid NaOH is added to a 100.0 mL buffer containing 0.13 M HClO and 0.37 M NaClO. The value of Ka for HClO is 2.9 × 10⁻⁸

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Question 42 of 47
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Determine the resulting pH when 0.003 mol of solid NaOH is added to a 100.0
mL buffer containing 0.13 M HCIO and 0.37 M NaCIO. The value of Ka for HCIO
is 2.9 x 10-8.
PREV
2
3
4
NEXT
>
Based on the result of the acid-base reaction, set up the ICE table in order to determine the
unknown.
HCIO(aq)
H20(1)
H3O*(aq)
CIO (aq)
+
Initial (M)
Change (M)
Equilibrium (M)
O RESET
0.13
0.37
0.010
0.040
0.10
0.40
+x
0.13 + x
0.13 - x
0.010 + x
0.010 - x
0.040 + x
0.040 - x
-X
0.10 + x
0.10 - x
0.40 + x
0.40 - x
9,529
3
étv
Transcribed Image Text:Chrome File Edit View History Bookmarks People Tab Window Help * ? 82% Sat 5:04 PM NetNutritiono b Answered: Which one of the fo x 101 Chem101 + A app.101edu.co Update : Question 42 of 47 Submit Determine the resulting pH when 0.003 mol of solid NaOH is added to a 100.0 mL buffer containing 0.13 M HCIO and 0.37 M NaCIO. The value of Ka for HCIO is 2.9 x 10-8. PREV 2 3 4 NEXT > Based on the result of the acid-base reaction, set up the ICE table in order to determine the unknown. HCIO(aq) H20(1) H3O*(aq) CIO (aq) + Initial (M) Change (M) Equilibrium (M) O RESET 0.13 0.37 0.010 0.040 0.10 0.40 +x 0.13 + x 0.13 - x 0.010 + x 0.010 - x 0.040 + x 0.040 - x -X 0.10 + x 0.10 - x 0.40 + x 0.40 - x 9,529 3 étv
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* ? 82%
Sat 5:04 PM
O NetNutrition®
b Answered: Which one of the fo x
101 Chem101
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Update :
Question 42 of 47
Submit
Determine the resulting pH when 0.003 mol of solid NaOH is added to a 100.0
mL buffer containing 0.13 M HCIO and 0.37 M NaCIO. The value of Ka for HCIO
is 2.9 x 10-8.
1
2
3
4
NEXT
>
Use the table below to determine the moles of reactant and product after the reaction of the acid
and base. You can ignore the amount of liquid water in the reaction.
HCIO(aq)
OH (aq)
H20(1)
CIO (aq)
+
+
Before (mol)
Change (mol)
After (mol)
2 RESET
0.13
0.37
+x
0.13 + x
0.13 - x
0.37 +x
0.37 - x
0.003
-0.003
0.013
-0.013
0.037
-0.037
0.010
-0.010
0.040
-0.040
9,529
3
étv
Transcribed Image Text:Chrome File Edit View History Bookmarks People Tab Window Help * ? 82% Sat 5:04 PM O NetNutrition® b Answered: Which one of the fo x 101 Chem101 + A app.101edu.co Update : Question 42 of 47 Submit Determine the resulting pH when 0.003 mol of solid NaOH is added to a 100.0 mL buffer containing 0.13 M HCIO and 0.37 M NaCIO. The value of Ka for HCIO is 2.9 x 10-8. 1 2 3 4 NEXT > Use the table below to determine the moles of reactant and product after the reaction of the acid and base. You can ignore the amount of liquid water in the reaction. HCIO(aq) OH (aq) H20(1) CIO (aq) + + Before (mol) Change (mol) After (mol) 2 RESET 0.13 0.37 +x 0.13 + x 0.13 - x 0.37 +x 0.37 - x 0.003 -0.003 0.013 -0.013 0.037 -0.037 0.010 -0.010 0.040 -0.040 9,529 3 étv
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