Determine the standard deviation of the sampling O 028284 (Round to six decimal places as needed.) Р (b) What is the probability of obtaining x = 46 or more individuals with the characteristic? That is, what is P(p≥ 0.23)? P(p≥ 0.23) = (Round to four decimal places as needed.)
Determine the standard deviation of the sampling O 028284 (Round to six decimal places as needed.) Р (b) What is the probability of obtaining x = 46 or more individuals with the characteristic? That is, what is P(p≥ 0.23)? P(p≥ 0.23) = (Round to four decimal places as needed.)
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
Related questions
Question
Solve For B)
![Suppose a simple random sample of size n = 200 is obtained from a population whose size is N = 15,000 and whose population proportion with a specified characteristic is p = 0.2
Click here to view the standard normal distribution table (page 1).
Click here to view the standard normal distribution table (page 2).
(a) Describe the sampling distribution of p
Choose the phrase that best describes the shape of the sampling distribution below.
A. Not normal because n ≤0.05N and np(1-p) < 10
B. Approximately normal because n ≤0.05N and np(1 - p) ≥ 10.
OC. Approximately normal because n ≤0.05N and np(1 - p) < 10.
OD. Not normal because n≤0.05N and np(1 - p) ≥ 10.
Determine the mean of the sampling distribution of p
HA= 2 (Round to one decimal place as needed.)
P
Determine the standard deviation of the sampling distribution of p.
op
O 028284 (Round to six decimal places as needed.)
(b) What is the probability of obtaining x = 46 or more individuals with the characteristic? That is, what is P(p≥ 0.23)?
P(p ≥ 0.23)= (Round to four decimal places as needed.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd6d3daef-83ca-43db-8d62-19d3f838a3b5%2Fd3f8b708-917b-43e4-afba-1cea45d91e6b%2Frwmsp2j_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Suppose a simple random sample of size n = 200 is obtained from a population whose size is N = 15,000 and whose population proportion with a specified characteristic is p = 0.2
Click here to view the standard normal distribution table (page 1).
Click here to view the standard normal distribution table (page 2).
(a) Describe the sampling distribution of p
Choose the phrase that best describes the shape of the sampling distribution below.
A. Not normal because n ≤0.05N and np(1-p) < 10
B. Approximately normal because n ≤0.05N and np(1 - p) ≥ 10.
OC. Approximately normal because n ≤0.05N and np(1 - p) < 10.
OD. Not normal because n≤0.05N and np(1 - p) ≥ 10.
Determine the mean of the sampling distribution of p
HA= 2 (Round to one decimal place as needed.)
P
Determine the standard deviation of the sampling distribution of p.
op
O 028284 (Round to six decimal places as needed.)
(b) What is the probability of obtaining x = 46 or more individuals with the characteristic? That is, what is P(p≥ 0.23)?
P(p ≥ 0.23)= (Round to four decimal places as needed.)
![Standard Normal Distribution Table (page 1)
Area
N
-3.4
-3.3
-3,2
-3.1
-3.0
-29
-2.8
-2.7
-2.6
<-2.5
-2.4
-2.1
-2.0
-1.8
0.00
0:0003
0.0005
0.0007
0.0010
0.0013
0.0019
0.0026
0.0035
0.0047
0.0062
0.0082
0.0107
0.0139
0.0179
0.0228
0.0287
0.0359
0.01
0.0003
0.0005
0.0007
0.0009
0.0013
0.0018
0.0025
0.0034
0.0045
0.0060
0.0080
0.0104
0.0136
0.0174
0.0222
0.0281
0.0351
0.02
0.0003
0.0005
0.0006
0.0009
0.0013
0.0018
0.0024
0.0033
0.0044
0.0059
0.0078
0.0102
0.0132
0.0170
0.0217
0.0274
0.0344
Standard Normal Distribution
0.03
0.04
0.05
0.0003
0.0004
0.0006
0.0009
0.0012
0.0017
0.0023
0.0032
0.0043
0.0057
0.0075
0.0099
0.0129
0.0166
0.0212
0.0268
0.0336
0.0003
0.0004
0.0006
0.0008
0.0012
0.0016
0,0023
0.0031
0.0041
0.0055
0.0073
0.0096
0.0125
0.0162
0.0207
0.0262
0.0329
0.0003
0.0004
0.0006
0.0008
0.0011
0.0016
0.0022
0.0030
0.0040
0.0054
0.0071
0.0094
0.0122
0.0158
0.0202
0.0256
0.0322
0.06
0.0003
0.0004
0.0006
0.0008
0.0011
0.0015
0.0021
0.0029
0.0039
0.0052
0.0069
0.0091
0.0119
0.0154
0.0197
0.0250
0.0314
0.07
0.0003
0.0004
0.0005
0.0008
0.0011
0.0015
0.0021
0.0028
0.0038
0.0051
0.0068
0.0089
0.0116
0.0150
0.0192
0.0244
0.0307
0.08
0.0003
0.0004
0.0005
0.0007
0.0010
0.0014
0.0020
0.0027
0.0037
0.0049
0.0066
0.0087
0.0113
0.0146
0.0188
0.0230
0.0301
0.09
0.0002
0.0003
0.0005
0.0007
0.0010
0.0014
0.0019
0.0026
0.0036
0.0048
0.0064
0.0084
0.0110
0.0143
0.0183
0.0233
0.0294](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd6d3daef-83ca-43db-8d62-19d3f838a3b5%2Fd3f8b708-917b-43e4-afba-1cea45d91e6b%2Fpgot0fr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Standard Normal Distribution Table (page 1)
Area
N
-3.4
-3.3
-3,2
-3.1
-3.0
-29
-2.8
-2.7
-2.6
<-2.5
-2.4
-2.1
-2.0
-1.8
0.00
0:0003
0.0005
0.0007
0.0010
0.0013
0.0019
0.0026
0.0035
0.0047
0.0062
0.0082
0.0107
0.0139
0.0179
0.0228
0.0287
0.0359
0.01
0.0003
0.0005
0.0007
0.0009
0.0013
0.0018
0.0025
0.0034
0.0045
0.0060
0.0080
0.0104
0.0136
0.0174
0.0222
0.0281
0.0351
0.02
0.0003
0.0005
0.0006
0.0009
0.0013
0.0018
0.0024
0.0033
0.0044
0.0059
0.0078
0.0102
0.0132
0.0170
0.0217
0.0274
0.0344
Standard Normal Distribution
0.03
0.04
0.05
0.0003
0.0004
0.0006
0.0009
0.0012
0.0017
0.0023
0.0032
0.0043
0.0057
0.0075
0.0099
0.0129
0.0166
0.0212
0.0268
0.0336
0.0003
0.0004
0.0006
0.0008
0.0012
0.0016
0,0023
0.0031
0.0041
0.0055
0.0073
0.0096
0.0125
0.0162
0.0207
0.0262
0.0329
0.0003
0.0004
0.0006
0.0008
0.0011
0.0016
0.0022
0.0030
0.0040
0.0054
0.0071
0.0094
0.0122
0.0158
0.0202
0.0256
0.0322
0.06
0.0003
0.0004
0.0006
0.0008
0.0011
0.0015
0.0021
0.0029
0.0039
0.0052
0.0069
0.0091
0.0119
0.0154
0.0197
0.0250
0.0314
0.07
0.0003
0.0004
0.0005
0.0008
0.0011
0.0015
0.0021
0.0028
0.0038
0.0051
0.0068
0.0089
0.0116
0.0150
0.0192
0.0244
0.0307
0.08
0.0003
0.0004
0.0005
0.0007
0.0010
0.0014
0.0020
0.0027
0.0037
0.0049
0.0066
0.0087
0.0113
0.0146
0.0188
0.0230
0.0301
0.09
0.0002
0.0003
0.0005
0.0007
0.0010
0.0014
0.0019
0.0026
0.0036
0.0048
0.0064
0.0084
0.0110
0.0143
0.0183
0.0233
0.0294
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