Determine the voltage regulation of a 2,000-V, 1-phase alternator giving a current of 100 A at 0.8 p.f. leading from the test results. Full-load current of 100 A is produced on short-circuit by a field excitation of 2.5 A. An e.m.f. of 500 V is produced on open-circuit by the same excitation. The armature resistance is 0.8 Ω . Draw the vector diagram 4. Determine the voltage regulation of a 2,000-V, 1-phase alternator giving a current of 100 A at 0.8 p.f.leading from the test results. Full-load current of 100 A is produced on short-circuit by a field excitation of 2.5A. An e.m.f. of 500 V is produced on open-circuit by the same excitation. The armature resistance is 0.8 N.Draw the vector diagram. [-8.9%]

For a 1-phase alternator,The full load voltage, VFL = 2000VCurrent, I=100APower factor,…

Determine the voltage regulation of a 2,000-V, 1-phase alternator giving a current of 100 A at 0.8 p.f. leading from the test results. Full-load current of 100 A is produced on short-circuit by a field excitation of 2.5 A. An e.m.f. of 500 V is produced on open-circuit by the same excitation. The armature resistance is 0.8 Ω . Draw the vector diagram

Determine the voltage regulation of a 2,000-V, 1-phase alternator giving a current of 100 A at 0.8 p.f. leading from the test results. Full-load current of 100 A is produced on short-circuit by a field excitation of 2.5 A. An e.m.f. of 500 V is produced on open-circuit by the same excitation. The armature resistance is 0.8 Ω . Draw the vector diagram

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter12: Power System Controls

Section: Chapter Questions

Problem 12.4P

See similar textbooks

Similar questions

Find the synchronous impedance and reactance of an alternator in which a given field current produces an armature current of 300A on short-circuit and generated emf of 40V on an open-circuit. The armature resistance is 0.1 ohm. To what induced voltage must the alternator be excited if it is to deliver a load of 100A at pf of lagging, with a terminal voltage of 300V.
Determine the efficiency of a 1500kVA, 2300-V, 3-phase, Wye connected alternator, which operates at a rated output, with a power factor of 80%, The DC armature resistance at 0.08-ohm. The field takes a 70-Aat 120-V from the exciter equipment. Friction and windage losses are 35-kW, iron losses is 15-kW and stray power losses is 1.2-kW. The effective armature winding resistance is 1.8 times the DC value.
6. The relation between the field current and the armature current in an alternator with the armature short-circuited can be shown byA. a rated-current 80% pf saturation curve.B. a synchronous impedance curve.C. an open-circuit saturation curve.D. a zero-power-factor regulation curve.
Determine the efficiency of a 1500kVA, 2300 V, 3 –phase, Y – connected alternator which operates at rated output with a power factor of 80%. The DC armature resistance at 70º C between terminals is 0.08 ohm. The field takes 70 A at 120 V from the exciter equipment. Friction and windage losses are 15kW, iron loss is 35kW and stray load losses is 15 kW. Assume the effective armature winding resistance is 1.5 times the DC value. a. 94.56 % b. 90.31 % b. 93.35 % d. 92.62 %
Determine the efficiency of 1500kVA, 2300V, 3phase, Y-connected alternator, which operates at rated output with a power factor of 80%. The DC armature resistance at 70°C between terminals is 0.08Ω. The field takes 70A at a 120V from the exciter equipment. Friction and windage loss are 15kW, iron loss is 35kW and stray load losses is 1.5kW. Assume the effective armature winding resistance is 1.5 times the DC value.
Find the synchronous impedance and reactance of an alternator in which a given field current produces an amature current of 200A on short-circuit and generated emf of 50V on an open-circuit. T he armature resistance is 0.1 ohm. To what induced voltage must the alternator be excited if it is to deliver a load of 100 A at pf of lagging., with a ternminal voltage of 200V.
A 2-pole, single-phase alternator driven at 3000rpm require a mechanical input to its rotor of 30kW when it is delivering its full-load output of 30kW. Under this condition the fixed and variable losses are1100W and 2.8kW respectively, and the rotor field winding is supplied from a 110V dc source. Given that the full-load efficiency is 87%, determine. the frequency generated, the input driving torque on full-load and the rotor field current
A 50-kVA, 550-volt single phase alternator draws a field current 10 A at rated load. With the same field current, the open circuit emf and short-circuit currents are 300V and 150A. The ohmic resistance of the armature between terminals is 0.18ohm. The ratio of effective to ohmic resistance maybe taken as 1.5. Determine the regulation at 0.8 power factor lagging. *Well Explained
Determine the efficiency of a 1500kVA, 2300 V, 3 phase, Y-connected alternator, which operatesat rated output with a power factor of 80%. The DC armature resistance at 70°C betweenterminals is 0.08 ohm. The field takes 70 A at 120 V from the exciter equipment. Friction andwindage losses are 15kW, iron loss is 35kW and stray load losses is 1.5kW. Assume the effectivearmature winding resistance is 1.5 times the DC value.
A three-phase alternator, 20 kV, synchronous has a reactance of 10Ω and a negligible resistance. The machine draws an armature current of 150A, 0.80 pf lagging. If the steam admission is constant and field current isadjusted raising the induced emf by 25 %, find the new armature current.
Determine the efficiency of a 1200 kVA, 4160 Volts, 3-phase, Y-connected alternator, which operates at rated output with a power factor of 83%. The DC armature resistance at 70 degree C between terminals is 0.10 ohm. The field takes 75 amps at 115 Volts from the exciter equipment. Friction and windage losses are 15 kW, iron loss is 40 kW and stray load losses is 1.75 kW. Assume the effective armature winding resistance is 1.65 times the DC value.
Show that an alternator running in parallel on constant-voltage and frequency bus-bars has a natural time period of oscillation. Deduce a formula for the time of one complete oscillation and calculate its value for a 5000-kVA, 3-phase, 10,000-V machine running at 1500 r.p.m. on constant 50-Hz bus-bars. The moment of inertia of the whole moving system is 14,112 kg-m2 and the steady short-circuit is five times the normal full-load value. ANSWER IS [1.33 second]