Determine the x and y components of F, and F, acting on the boom shown in Fig. 2-18a. Express each force as a Cartesian vector. 158 F-200 N 200N 30 -fx fx 1-260 N 13 (5) fy =Fcoso 260 12 = 200 Cos (30) E 173.2 \
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- Resolve the force F=20i+30j+50klb into two components-one perpendicular to plane ABC and the other lying in plane ABC.The intensity of the line loading acting on a quarter circle is w=w0(2/). Use intergration to determine the resultant of the loading and its line of action.The pole OB is subjected to the 6004b force at B. Determine (a) the rectangular components of the force; and (b) the angles between the force vector and the coordinate axes.
- Find the internal force systems acting on sections 1 and 2.Expiremental Method: Force Table F1 - 150N, 30° N of E F2 - 100N, 60° E of S 1) Find the Equilibrant Magnitude and Equilibrant Direction 2) Find Resultant Force Vector Magnitude and %Error 3) Find Resultant Force Vector Direction and %Error1. R is the resultant coplanar-concurrent forces composing of P, T, F, and each Q acting on a body. Find the magnitude of the fourth force Q and its angle with respect to horizontal, if P = 840N directed downward to the left at 20 degrees with the vertical, T = 890N is acting to the right along the horizontal, F = 530N is up to the right at 45 degrees with the horizontal and R = 1300N acting downward to the right 30 degrees with the horizontal. show solution, formula and the sketch of the FBD and pls write legible
- 1. R is the resultant coplanar-concurrent forces composing of P, T, F, and each Q acting on a body. Find the magnitude of the fourth force Q and its angle with respect to horizontal, if P = 840N directed downward to the left at 20 degrees with the vertical, T = 890N is acting to the right along the horizontal, F = 530N is up to the right at 45 degrees with the horizontal and R = 1300N acting downward to the right 30 degrees with the horizontal.Using a suitable figure show that the resultant of two co-plainer, concurrent forces 'P' & 'Q' having '0' angle between them, can be written in the form of, R = square root of P^2+ Q^2 + 2PQ cos theta. Hence derive an expression for the resultant force if the angle between the forces is 90°.18 - Exspress the resultant force of the three forces as a vector form. Which following one is TRUE? unit vectors are i, j, k.A) Resultant force: (4 - 5.cos45 + 8.cos75).i + (5.sin45 - 8.cos75).jB) Resultant force: (5 + 4.cos45 - 8.cos75).i + (4.sin45 + 8.sin15).jC) Resultant force: (8 + 5.cos45 - 4.cos75).i - (5.sin45 + 4.sin75).jD) Resultant force: (4 + 5.cos45 - 8.cos75).i + (5.sin45 + 8.sin75).jE) Resultant force: (4 - 5.cos45 + 8.cos75).i + (5.sin45 - 8.sin75).j
- Three professional wrestlers are fighting over a champion’s belt, and each exerts a force on the belt. Wrestler 1 exerts a force F1 = 40.0 N in the +x-direction, wrestler 2 exerts a force F2 = 80.0 N in the -y-direction, and wrestler 3 exerts a force F3 = 60.0 N at an angle of 36.9° counterclockwise from the +x-direction. Find the xand y-components of the net external force on the belt, and find the force’s magnitude and direction.Answer for the 1st part of the problem. magnitude of force A = 74 N direction of force A = 25o north of west second force = P direction of force P = α south of west arrow_forward The resultant of two forces is horizontal , it means that the y component of resultant = 0 Ry = ASin(25o) - PSin(α) 0 = (74×0.42) - PSin(α) PSin(α) = 31.08 NFor, the smallest force P , the value of Sinα must be maximum which is 1 when the value of αis 90 degree Thus, P×Sin(90o) = 31.08 N P = 31.08 N The magnitude of smallest force P = 31.08 N the direction of force P = 90 degree south of west = along - y axis= arrow pointing vertically downwSITUATION 6: From the given set of forces shown in the Fig. ENG-228, determine the following: X-component of the resultant force of the system (N) (Answer: 47.26) and Y-component of the resultant of the force system (N). (Answer: 60.97) The angle (degrees) that the resultant force makes with the horizontal measured CCW. (Answer: 52.22) The distance (m) from the origin where the resultant intersects the x-axis. (Answer: 6.06)