Q1 (2-93): The plate is suspended using the three cables which exert the forces shown. Express each force as a Cartesian vector. Given: FBA = 3.5kN FCA = 5kN FDA = 4kN a = 0.3m b = 0.3m c = 0.6m d = 1.4m e = 0.3m f = 0.3m 9 = 0.2m FCA FRA C FDA B

International Edition---engineering Mechanics: Statics, 4th Edition
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Chapter7: Dry Friction
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Q1 (2-93):
The plate is suspended using the three cables which exert the forces shown.
Express each force as a Cartesian vector.
Given:
FBA = 3.5kN
FCA = 5kN
FDA = 4kN
a = 0.3m
b = 0.3m
c = 0.6m
d = 1.4m
e = 0.3m
f = 0.3m
9 = 0.2m
FCA
FRA
FDA
Transcribed Image Text:Q1 (2-93): The plate is suspended using the three cables which exert the forces shown. Express each force as a Cartesian vector. Given: FBA = 3.5kN FCA = 5kN FDA = 4kN a = 0.3m b = 0.3m c = 0.6m d = 1.4m e = 0.3m f = 0.3m 9 = 0.2m FCA FRA FDA
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