Determine whether the following series converges. Justify your answer. 2 Σ √6k k=1 V 6k

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Determine whether the following series converges. Justify your answer.
∞
2
Σ
k=1 √6ke√6k
Select the correct choice below and fill in the answer box to complete your choice.
(Type an exact answer.)
O A. The series is a geometric series with common ratio so the series converges by the properties of a geometric series.
1
B. The Integral Test yields
∞
S Fix
1
f(x) dx =
∞
OC. The Integral Test yields [f(x) dx:
1
so the series converges by the Integral Test.
so the series diverges by the Integral Test.
D. The series is a p-series with p =
E.
The series is a p-series with p =
F. The series is a geometric series with common ratio
so the series converges by the properties of a p-series.
so the series diverges by the properties of a p-series.
so the series diverge Screenshot
3
of a geometric series.
Transcribed Image Text:Determine whether the following series converges. Justify your answer. ∞ 2 Σ k=1 √6ke√6k Select the correct choice below and fill in the answer box to complete your choice. (Type an exact answer.) O A. The series is a geometric series with common ratio so the series converges by the properties of a geometric series. 1 B. The Integral Test yields ∞ S Fix 1 f(x) dx = ∞ OC. The Integral Test yields [f(x) dx: 1 so the series converges by the Integral Test. so the series diverges by the Integral Test. D. The series is a p-series with p = E. The series is a p-series with p = F. The series is a geometric series with common ratio so the series converges by the properties of a p-series. so the series diverges by the properties of a p-series. so the series diverge Screenshot 3 of a geometric series.
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