Determine whether the ordered pair is a solution of the given system of equations. Remember to use alphabetical order of variables. (6,7); 2x - y = 5 4x - Зу%3D3 Is the ordered pair a solution? A. No, it is not a solution because the ordered pair (6,7) makes the first equation true but the second equation false. B. Yes, it is a solution because the ordered pair (6,7) makes both equations true. C. No, it is not a solution because the ordered pair (6,7) makes both equations false. O D. No, it is not a solution because the ordered pair (6,7) makes the second equation true but the first equation false.

College Algebra (MindTap Course List)
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ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
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Chapter6: Linear Systems
Section6.1: Systems Of Linear Equations
Problem 83E: Use the system of three equations in three variables to solve each problem. Work schedules A college...
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Determine whether the ordered pair is a solution of the given system of equations. Remember to use alphabetical order of variables.
(6,7);
2х - у%35
4x - 3y = 3
Is the ordered pair a solution?
O A. No, it is not a solution because the ordered pair (6,7) makes the first equation true but the second equation false.
B. Yes, it is a solution because the ordered pair (6,7) makes both equations true.
C. No, it is not a solution because the ordered pair (6,7) makes both equations false.
D. No, it is not a solution because the ordered pair (6,7) makes the second equation true but the first equation false.
Transcribed Image Text:Determine whether the ordered pair is a solution of the given system of equations. Remember to use alphabetical order of variables. (6,7); 2х - у%35 4x - 3y = 3 Is the ordered pair a solution? O A. No, it is not a solution because the ordered pair (6,7) makes the first equation true but the second equation false. B. Yes, it is a solution because the ordered pair (6,7) makes both equations true. C. No, it is not a solution because the ordered pair (6,7) makes both equations false. D. No, it is not a solution because the ordered pair (6,7) makes the second equation true but the first equation false.
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