Determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. If fx(xo, Yo) = f(xo, Yo) = 0, then f has a relative extremum at ( (xo, Yo, ²o). True. False. f(x, y) = x² - y² then fx(0, 0) = f(0, 0) = 0, but (0, 0, 0) is a saddle point. False. f(x, y) = 1 - x² - y²has a relative maximum at (0, 0, 0). False. f(x, y, z) = x² + y² + z²has a relative minimum at (0, 0, 0).

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.6: Variation
Problem 2E
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Determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false.
If fx(xo, Yo) = f(xo, Yo) = 0, then f has a relative extremum at (
(xo, Yo, ²o).
True.
False. f(x, y) = x² - y² then fx(0, 0) = f(0, 0) = 0, but (0, 0, 0) is a saddle point.
False. f(x, y) = 1 - x² - y²has a relative maximum at (0, 0, 0).
False. f(x, y, z) = x² + y² + z²has a relative minimum at (0, 0, 0).
Transcribed Image Text:Determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. If fx(xo, Yo) = f(xo, Yo) = 0, then f has a relative extremum at ( (xo, Yo, ²o). True. False. f(x, y) = x² - y² then fx(0, 0) = f(0, 0) = 0, but (0, 0, 0) is a saddle point. False. f(x, y) = 1 - x² - y²has a relative maximum at (0, 0, 0). False. f(x, y, z) = x² + y² + z²has a relative minimum at (0, 0, 0).
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