Determine which of the following three alternatives is most efficient and which one is more profitable using the incremental benefit/cost method. The rate is 5% per year. Alter. Construction cost$ Annual Salvage $ Life (yrs) Benefits Slyr $450,000 $1,100,000 $750,000 A $320,000 $360,000 $330,000 $40,000 $100,000 -20,000 10 B 15 13
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- Consider these two alternatives.Alternative A Alternative BCapital investment OMR 6000 7500Annual revenues OMR 1800 2250Annual expenses OMR 500 750Estimated market valueOMR1200 1600Useful life 10 10MARR 12% 1. Recommend which alternative should be selected.2. How much capital investment of the expensive alternative have to vary so that theinitial decision would be reversed.It is proposed to place a cable on existing pole line along the shore of a lake to connect two points on opposite sides. Which is more economical? Compare alternatives using the following methods:a) ROR on Additional Investment Methodb) Annual Cost Methodc) Equivalent Uniform Annual Cost Methodd) Present Worth Cost Method Show complete manual solutionFitzgerald, Ivy, Garcia, Nichols, Eudy, Williams, Thomas, Owens, and Nagy (FIGNEWTON) Inc. must replace its fig - crushing equipment. The alternatives under consideration are presented below. Alternative First Cost Net Annual Benefits Useful Life A $170, 500 $14, 675 5 years B 205,000 17,000 7 years C 242,500 16, 350 8 years D 290,000 14,825 10 years a) Which anlaysis method should be used to select the alternative? b) Why should that analysis method be used? c) if FIGNEWTON uses a MARR of 8%, what alternative should be chosen? d) if FIGNEWTON uses a MARR of 18%, what alternative should be chosen? Submit one excel file with answers a), b), c) and d) highlighted clearly.
- Municipal Engineer wants to evaluate three alternatives for supplementing the water supply. 1st alternative – continue deep well pumping at an annual cost of $10,500 2nd alternative – install a 10” pipeline from a surface reservoir. First cost is $25,000 and annual pumping cost is $7,000 3rd alternative – install a 20” pipeline from the reservoir. First cost of $34,000 and annual pumping cost of $5,000. Life of all alternatives is 20 years. For the second and third alternatives, salvage value is 10% of first cost. With interest at 8%, which alternative should the engineer recommend? Use present worth analysis PW (deepwell) = ? PW (10”pipeline) = ? PW (20”pipeline) = ?It is proposed to place a cable on existing pole line along the shore of a lake to connect two points on opposite sides. Which is more economical?Compare alternatives using the following methods:a) ROR on Additional Investment Methodb) Annual Cost Methodc) Equivalent Uniform Annual Cost Methodd) Present Worth Cost MethodIf the B/C value is exactly 1.0 or very near 1.0, non-economic factors can assist make the decision for the best alternative. Select one: True False
- For these two AW relations, the breakeven point QBE in miles per year is closest to:AW1=-23,000(A/P,10%,10) + 4000(A/F,10%, 10) - 5000 - 4QBEAW2 =-8000(A/P,10%,4) - 2000 - 6QBEa. 1984b. 1224c. 1090d. 655A municipal power plant uses natural gas from an existing pipeline at an annual cost of $40,000 per year. A new pipeline would initially cost $100,000, but it would reduce the annual cost to $10,000 per year. (a) Assume an analysis period of 25 years and no salvage value for either pipeline. The interest rate is 6%. Using the equivalent uniform annual cost (EUAC), should the new pipeline be built? (b) The power plant uses natural gas. What are some of the noneconomic benefits to the municipality of this energy source over others? Develop three primary advantages and disadvantages.Alternative 3 is incorrect EUAC=( Equivalent Annaul COst of Initial Investment)+ (Expected Moderate annaual flood damage cost )+ (expected severe annaual flood cost )
- If the MARR=10%, compute the value of X that makes the alternatives equally desirable. Do not use spreadsheets. Alternatives Machine A Machine B First cost $12,000 $20,000 Annual Operating cost $1,400/year X Salvage value $2,000 $3,000 Life 4 years 8 yearsMotor A and B is providing 150hp and it is being used for 10 hours per day, 250 days in a year if the motor is using the electricity. Additional cost for both motors is the annual maintenance cost worth 1200 and other manufacturing overhead costing 550 per month. Motor A has an original price of 50,000 while 45000 for Motor B, and both have the salvage value of 3000 after 5 years. Machine efficiency is 92% and 90% respectively.A. How much is the electrical cost if the money is worth 15%? Electrical cost = pesos ( 2 decimal places ) B. With the same initial cost, salvage value, expected life, number of working days per year, annual maintenance cost and manufacturing overhead. How much is the fuel cost if the interest rate is 10% compounded annually if motor A needs to be refilled by 2L/ output while motor B requires a 3L/output, and the target output per day is 10 outputs?A new water treatment plant proposed for Anytown, has an initial cost of P56 million. The new plant will service the 7,500 residential customers for the next 30 years. It is expected to save each customer P125 per year. The plant will require a major overhaul every 5 years, costing P1 million. Determine the benefit/cost ratio at the city’s interest rate of 6%. (Use PW and EUAC) Please show the manual computation.