Diagonal elements of Cholesky factor. Each X ES+ has a unique Cholesky factorization X = LLT, where L is lower triangular, with Li> 0. Show that Lii is a concave function of X (with domain S2+). Hint. Lii can be expressed as Lii = (w - zTY-12) ¹/2, where is the leading ix i submatrix of X. Y T 2 W

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
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Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 91E
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3.27 Diagonal elements of Cholesky factor. Each X E S has a unique Cholesky factorization
X = LLT, where L is lower triangular, with Lü > 0. Show that Lii is a concave function
of X (with domain S).
Hint. Lii can be expressed as Lii = (w – zTY-12)/2, where
Y
T
w
is the leading i xi submatrix of X.
Transcribed Image Text:3.27 Diagonal elements of Cholesky factor. Each X E S has a unique Cholesky factorization X = LLT, where L is lower triangular, with Lü > 0. Show that Lii is a concave function of X (with domain S). Hint. Lii can be expressed as Lii = (w – zTY-12)/2, where Y T w is the leading i xi submatrix of X.
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