Need help with this Foundations of Mathematics homework problem. Below the homework problem is my work. I received feedback from my teacher and he said "You're proving that the product of an even and odd integer is even here; you need to prove that the product of two consecutive integers is even." 1. Prove that the product of two consecutive integers is even. Let m = 2k and n = 2l + 2. Thereby, m and n are two odd integers and k and l are integers. mn = (2k)(2l + 2) = (2)(k)(2)(l + 1) = 2(2kl + 2k) Proof Two integers which are added or multiplied are also integers, so (2
Need help with this Foundations of Mathematics homework problem. Below the homework problem is my work. I received feedback from my teacher and he said "You're proving that the product of an even and odd integer is even here; you need to prove that the product of two consecutive integers is even." 1. Prove that the product of two consecutive integers is even. Let m = 2k and n = 2l + 2. Thereby, m and n are two odd integers and k and l are integers. mn = (2k)(2l + 2) = (2)(k)(2)(l + 1) = 2(2kl + 2k) Proof Two integers which are added or multiplied are also integers, so (2
College Algebra (MindTap Course List)
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Chapter4: Polynomial And Rational Functions
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Need help with this Foundations of Mathematics homework problem. Below the homework problem is my work. I received feedback from my teacher and he said "You're proving that the product of an even and odd integer is even here; you need to prove that the product of two consecutive integers is even."
1. Prove that the product of two consecutive integers is even.
Let m = 2k and n = 2l + 2. Thereby, m and n are two odd integers and k and l are integers.
mn = (2k)(2l + 2) =
(2)(k)(2)(l + 1) =
2(2kl + 2k)
Proof
Two integers which are added or multiplied are also integers, so (2kl + 2k) is an integer also. As a result, 2(2kl + 2) is an odd integer.
This proves that the product of two consecutive integers is even.
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