Question
Asked Aug 21, 2019

Differentiate y=(3x+1)2

check_circleExpert Solution
Step 1

Given,

...
y = (3x 1)2
Now, differentiating
on both side with respect to x, we get
d((3x+1)2)
dy
dx
dx
= 2(3x + 1)2-1 d(3x+1)
dx
= 2(3x
1) x (3 x 1 + 0)
- 6(3x1)
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y = (3x 1)2 Now, differentiating on both side with respect to x, we get d((3x+1)2) dy dx dx = 2(3x + 1)2-1 d(3x+1) dx = 2(3x 1) x (3 x 1 + 0) - 6(3x1)

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Calculus

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