Dim a, b, i, sum As Integer Assume sum = 0 a = 8 b = 10 i = a Do i = i + 1 sum = sum + i Loop While i <= b Display sum = ________________________
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What is the output of the following Add codes? consider each case independently?
Dim a, b, i, sum As Integer
Assume sum = 0
a = 8
b = 10
i = a
Do
i = i + 1
sum = sum + i
Loop While i <= b
Display sum = ________________________
Step by step
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- Answer the given question with a proper explanation and step-by-step solution. please only add to code where it says " add code below this line" C++ pleaseI need to: Justify and Explain briefly in at least 3 sentences the complexity of each operation the code below in terms of Big O notation. Justify and discuss if there is any way to improve the complexity of the designed algorithms. #include <stdio.h> #include <stdlib.h> #include <string.h> #include <stdbool.h> struct Node { char data; struct Node *next; }; struct Node* head = NULL; void push(char val) { struct Node* newnode = (struct Node*) malloc(sizeof(struct Node)); newnode->data = val; newnode->next = head; head = newnode; } void pop() { if(head == NULL) printf("Stack Underflow\n"); else { printf("The popped element is: %c\n", head->data); head = head->next; } } void print_list(struct Node *head) { printf(" "); while(head) { printf("%c ", head->data); head = head->next; } printf("\n"); } bool isEmpty() { return head == NULL; } void delete_node(struct Node **head, struct Node…economics R code to extract time series data from U.S. Dollars to Euro Spot Exchange Rate (DEXUSEU)(Without errors) code i wrote: # Load fredr library library(fredr) # Set your FRED API key my_key <- "bdce4c95ff2211444fe957773c117072" # Retrieve U.S. Dollars to Euro Spot Exchange Rate (DEXUSEU) data from FRED USD_EUR <- fredr_series("DEXUSEU", observation_start = "2013-04-14", observation_end = "2023-04-14", api_key = my_key) # View the first few rows of the data head(USD_EUR) error i'm getting : Error in `check_dots_empty()`: ! `...` is not empty. These dots only exist to allow for future extensions, and should be empty. Did you misspecify an argument? Run `rlang::last_trace()` to see where the error occurred.
- A = [1 1; 1 -1];b = [80; 20]; A_inverse = inv(A);x = A\b; disp('A inverse is');disp(A_inverse);disp(['x1 is ', num2str(x(1)), ' and x2 is ', num2str(x(2))]); if isequal(round(x), [50; 30]) disp('Success');else disp('Incorrect: Please try again');end. Output matlab. .You are the sysadmin for a big tech company, and you have to estimate the amount of servers you need to handle some long-running jobs. One server can handle only one job at once. One job can only be executed by one server at once. Once a server has finished executing its current job, it can be reassigned to a new job. Given an array of time intervals intervals where intervals[i] = [starti, endi], representing the start and end time for a particular job that needs to be executed, return the minimum number of servers required to run all jobs. Constraints: 1 <= intervals.length <= 104 0 <= starti < endi <= 106 Function definition for Java: public int minMeetingRooms(int[][] intervals) { // Your code here } Function definition for Python: def minMeetingRooms(self, intervals: List[List[int]]) -> int: #Your code here Announced Test Cases: Input: intervals = [[0,30],[5,10],[15,20]] Output: 2Explanation: We need one server for the job that starts at 0. For the job…Convert from C to C++ .Thank you. / include all required libraries#include<stdio.h>#include<stdlib.h>#include<sys/types.h>#include<sys/wait.h>#include<unistd.h> // variable to store number of generationsint num_generations; // function to print the generationsvoid printGeneration(int n){// stop if number of generations are reachedif(n>num_generations)return; // create a forkpid_t p = fork(); // generate new generationsif(p==0)printGeneration(n+1);else if(p>0)wait(0); // wait until child process terminates // print the present generationif(p!=0){// if n is 0if(n==0)printf("Parent. "); // print parent// if n is 1else if(n==1)printf("Child. "); // print child// for all other caseselse{// print grandchildrenfor(int i=0;i<n-2;i++)printf("Great ");printf("Grandchild. ");}// print pid and ppidprintf("pid: %d ppid: %d\n",getpid(),getppid());}} // main functionint main(int argc, char* argv[]){// if no arguments are providedif(argc==1){// print…
- This is what i have for this code but a lot is worng and i dont know why # Step 1:beatles = []print("Step 1:", beatles) # Step 2:beatles = ["John Lennon", "Paul McCartney", "George Harrison"]print("Step 2:", beatles) # Step 3:new_members = []new_members = ["Stu Sutcliffe", "Pete Best"beatles.append(new_members)print("Step 3:", beatles), # Step 4:beatles.remove("Stu Sutcliffe")beatles.pop(1)print("Step 4:", beatles) # step 5beatles.insert(0, 'Ringo Starr')print("Step 5:", beatles)print("The Fab", len(beatles))Hello, I am having an error and cannot figure out how to solve this question. Could someone please assist? Please be advised, I am using PostgreSQL as that is what was used in class. Thus, I must use PLPGSQL Code CREATE OR REPLACE FUNCTION Moreno_03_bankTriggerFunction()RETURNS TRIGGERLANGUAGE PLPGSQLAS$$CREATE TRIGGER Wise_12_bankTriggerAFTER DELETE ON accountFOR EACH ROW EXECUTE PROCEDURE Moreno_15_bankTriggerFunction();Information is present in the screenshot and below. Based on that need help in solving the code for this problem in java. The time complexity has to be as less as possible (nlogn or n at best, no n^2). Apply divide and conquer algorithm in the problem. Make sure ALL test cases return expected outputs by providing output screenshots. Hint: Use bisection method / binarySearch Output FormatThe output contains one line with a single integer: the minimum instability you can achieve modulo 10^9 + 7. Sample Input 02 1 12343 Sample Output 030 Sample Input 12 2 2142151 Sample Output 140 Sample Input 22 5 64670132061622 Sample Output 2214 The actual code import java.io.*;import java.util.*; public class Solution { public static final long MOD = 1000000007L; public static void main(String[] args) throws Exception { BufferedReader br = new BufferedReader( new InputStreamReader(System.in) ); String[] parts =…
- Use java only. Problem: Write a program to compute lines equation for a set of lines. The number of lines is read from the user. Each line is computed by generating two points randomly using Point2D API. In addition, distance between two points is computed. The program should display a table which include all information about each line. See sample runs below. Take into consideration: 1. Number of generated lines should be greater than zero. 2. Two point objects are constructed only once. Then just update the location of two points for each line using Point2D API methods. 3. x and y values of each point are generated randomly to be less than 100 and greater than 0. 4. Compute the distance between two points using Point2D API methods. 5. A line has two special cases: horizontal line (m = 0), vertical line( m is undefined).Here is my entire code(average is not working yet). The response I got from the professor is that I have to create a DRY solution replacing the five display_functions with a single get_array function you call five times like common_array = get_array(plant_xml, "COMMON") etc. from urllib.request import urlopenfrom xml.etree.ElementTree import parse def read_data(data_file): plant_url = urlopen(data_file) plant_xml = parse(plant_url) return plant_xml def display_common_items(plant_xml): plant_root = plant_xml.getroot() common_array = [] for item in plant_root.findall("PLANT"): common_array.append(item.find("COMMON").text) return common_array def display_botanical_items(plant_xml): plant_root = plant_xml.getroot() botanical_array = [] for item in plant_root.findall("PLANT"): botanical_array.append(item.find("BOTANICAL").text) return botanical_array def display_zone_items(plant_xml): plant_root = plant_xml.getroot() zone_array = []…1.1 Using pd.get dummies(). turn the input X into one-hot encodings in the transform() function (). Save the result in the variable one hot1.2 Save the column names for our one-hot encoding one hot so we may retrieve them later if necessary. Save the result to the class self. feature names class OneHotEncoding(BaseEstimator, TransformerMixin): def__init__(self): self.feature_names = None deffit(self, X: pd.DataFrame, y: pd.DataFrame = None): # We don't need to set/learn any variables so # we just need to return a reference to the object with 'self' returnself deftransform(self, X: pd.DataFrame, y: pd.DataFrame = None): # TODO 1.1 one_hot = # TODO 1.2 self.feature_names = return one_hot