Dinitrogen tetroxide partially decomposes according to the following equilibrium: N2O4 (g) → 2NO2 (g) A 1.000-L flask is charged with 4.00 - 10-2 mol of N2O4. At equilibrium, 3.25 · 10-2 mol of N2O4 remains. Keq for this reaction is 0.995 O 6.94 · 10-3 O 0.212 O 3.00 - 10-4 0.459

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A: Below attached file showing the details answer. All the best.

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