Discuss the continuity of the function on the closed interval. Function Interval 1- x, f(x) = { 1 1 +-X, x > 0 [-2, 4] The function is discontinuous because f(-2) f(4). The function is continuous because lim f(x) and lim f(x) both exist. x--2 X→4¬ The function is continuous because lim f(x) = lim f(x) = f(0) = 1. x-0 オ→o+ The function is continuous because the domain boundary is not inside the interval [-2, 4]. The function is discontinuous because all piecewise functions are discontinuous at their domain boundaries.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.5: Rational Functions
Problem 54E
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Discuss the continuity of the function on the closed interval.
Function
Interval
1 – x,
f(x) =
[-2, 4]
1 +-X,
2
x > 0
The function is discontinuous because f(-2) f(4).
The function is continuous because lim flx) and lim f(x) both exist.
x--2+
x-4
The function is continuous because lim f(x)
= lim f(x) = f(0) = 1.
The function is continuous because the domain boundary is not inside the interval [-2, 4].
The function is discontinuous because all piecewise functions are discontinuous at their domain boundaries.
DELL
DII
F6
Transcribed Image Text:Discuss the continuity of the function on the closed interval. Function Interval 1 – x, f(x) = [-2, 4] 1 +-X, 2 x > 0 The function is discontinuous because f(-2) f(4). The function is continuous because lim flx) and lim f(x) both exist. x--2+ x-4 The function is continuous because lim f(x) = lim f(x) = f(0) = 1. The function is continuous because the domain boundary is not inside the interval [-2, 4]. The function is discontinuous because all piecewise functions are discontinuous at their domain boundaries. DELL DII F6
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