DL readings significantly lov -xide diffusing capacity for 103.768 88.602 02 205 61. 675

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.6: Summarizing Categorical Data
Problem 4BGP
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Researchers have shown that cigarette smoking has a deleterious effect on lung function.
In their study of the effect of cigarette smoking on the carbon monoxide diffusing capacity
(DL) of the lung, Ronald Knudson, W. Kaltenborn and B. Burrows found that current
smokers had DL readings significantly lower than either ex-smokers or nonsmokers. The
carbon monoxide diffusing capacity for a random sample of current smokers was as
follows:
103.768
88.602 73.003 123.086
91.052
92.295
61.675 90.677
84.023
76.014
100.615
88.017 71.210 82.115
89.222
102.754 108.579 73.154 106.755
90.479
Do these data indicate that the mean DL reading for current smokers is lower than 100,
the
average DL reading for nonsmokers?
A. Find the test statistics and interpret the results, a = 0.01?
B. Calculate p value and interpret the results.
C. Find the confidence interval for a = 0.05.
Transcribed Image Text:Researchers have shown that cigarette smoking has a deleterious effect on lung function. In their study of the effect of cigarette smoking on the carbon monoxide diffusing capacity (DL) of the lung, Ronald Knudson, W. Kaltenborn and B. Burrows found that current smokers had DL readings significantly lower than either ex-smokers or nonsmokers. The carbon monoxide diffusing capacity for a random sample of current smokers was as follows: 103.768 88.602 73.003 123.086 91.052 92.295 61.675 90.677 84.023 76.014 100.615 88.017 71.210 82.115 89.222 102.754 108.579 73.154 106.755 90.479 Do these data indicate that the mean DL reading for current smokers is lower than 100, the average DL reading for nonsmokers? A. Find the test statistics and interpret the results, a = 0.01? B. Calculate p value and interpret the results. C. Find the confidence interval for a = 0.05.
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