Why is the sum of un factored load instead of the factored load used for determining the width of the footing? Document1- Microsoft WordAaBbCcl AaBbC AaBbCcI AaBbC AaBbCc AaBbCc.前、 ,。I NormalTitle1 No Spaci...Heading 1Heading 2SubtitleвgraphStylesQ#5:a)Why is the suin of un-factored loads instead ofsum of the factored loads used for determiningthe width of footings? Please justify youranswers with logical reasons.=150 k.

Answered: Image /qna-images/answer/e0b30ba7-3e4d-4975-8f7f-608346bf9be2.jpg

Document1- Microsoft Word AaBbCcl AaBbC AaBbCcI AaBbC AaBbCc AaBbCc. 前、 ,。 I Normal Title T No Spaci... Heading 1 Heading 2 Subtitle agraph Styles Q#5: a)Why is the suin of un-factored loads instead of sum of the factored loads used for determining the width of footings? Please justify your answers with logical reasons. = 150 k.

Document1- Microsoft Word AaBbCcl AaBbC AaBbCcI AaBbC AaBbCc AaBbCc. 前、 ,。 I Normal Title T No Spaci... Heading 1 Heading 2 Subtitle agraph Styles Q#5: a)Why is the suin of un-factored loads instead of sum of the factored loads used for determining the width of footings? Please justify your answers with logical reasons. = 150 k.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A rectangular footing has a dimensions shown and is acted upon by a dead load of 722 kN and a live load of 620 kN. The column dimension is 326 x 662 mm where he shorter dimension is parallel to B The thickness of the footing is 408mm. f'c=28 MPa and fy=420 MPa for diameter 20mm bars. A=3.1m and B=5.1m
Problem attached Twoplate-loadtestsona sandy soilwereperformedusingplates 0.3×0.3mand0.6×0.6m.For a 20mmsettlement, theloadswere 30and72kN,respectively. FinddimensionBof a square footing requiredto carry a200 kNcolumnloadwithan allowable settlement of 20mm, (a) assume extrapolating plate-load test results to the footing size is approximatelyjustified and the bearing load V increases linearly with B (for the given settlement), (b) use Housel’s method.
GEOTECHNICAL ENGINEERINGFind the value of B if the Allowable load for the footing Qa = 580KN
A rectangular footing has dimensions shown and is acted upon by a dead load of 584 kN and a live load of 412 kN. The column dimension is 399x719 mm where the shorter dimension is parallel to B. The thickness of the footing is 696mm. fc=28 MPa and fy=420 MPa for diameter 20mm bars. A=2.8m and B=5.7m Calculate the number of bars along the long direction
What is the amount of loadthat applied to the center ofthe rectangular concrete beamsample if the Modulus ofRupture is 3.50MPa?Length of the sample = 550mmDimension: 150mm x150mm
Define the By Bowle's method ?
SFD and BMD by graphical method - distributed load
Please answrr it asap for an upvote. Thankyou 15 points Item at position 3 If a square footing with 2.4 m dimension is embedded into the ground at a depth of 1.03m with x = 0.37m and y = 0.19m, determine the gross allowable bearing capacity of the footing. Assume a soil with cohesion = 11 kPa, unit weight = 17.80 kN/m3 and \phiϕ = 31 degrees. The factor of safety is 3
Shall reversible moisture movement be taken into account in estimating movementfor movement joints?
For a 400 x 400mm column carrying a DL of 500KN and aLL of 1000KN. Soil bearing capacity (SBC) = 207MPa, fy = 413.7MPa.Using 2010/2015 NSCP Code. Considering weight of footing and soilabove footing to be 7% of the total service load, design thefollowing:a) Minimum allowable length of an edge of a square footing tosafely carry the service loads. b) Minimum thickness of footing required if 16mm diameter barsare to be used both ways. c) Number of 16mm diameter bottom bars required.
---Continuation of my recently posted question---A rectangular footing has dimensions shown and is acted upon by a dead load of 1200 kN and a live load of 1600 kN. The column dimension is 300x600 where the shorter dimension is parallel to B. The thickness of the footing is 500mm. F'c = 28 MPa and fy = 420 MPa for diameter 20mm bars. A = 2.4m and B = 4.2m Calculate the following:1.)The Punching shear force, kN2.)The Ultimate Punching Shear stress, MPa3.)The Critical Moment, kN-m4.)Is the given footing adequate for the given loads? Yes or No? Explain
Pls help thanks