Draw a state-space till number 15 where the starting state is number 1 and each state n has two successors: 2n and 2n + 1; Consider two scenarios where the Goal states are 10 and 6 respectively, identify which technique (BFS or DFS) will be suitable to reach the goal quickly. And how
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Draw a state-space till number 15 where the starting state is number 1 and each state n has two successors: 2n and 2n + 1; Consider two scenarios where the Goal states are 10 and 6 respectively, identify which technique (BFS or DFS) will be suitable to reach the goal quickly. And how.
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- Make sure your response addresses the following items. What are the values of b,l for the indicated start state if states are represented by (b,l)? Prove that P((b,l)) is true for the indicated start state. What does assuming P((b,l)) to be true translate to mean within the context of this problem? Prove that P((b,l))⟹P(δi(b,l)) for any of the possible transitions δi where i∈{1,2,3,4}. Use the fact that P((b,l)) is true for any reachable state to show that no player will ever win the game. Please answer all questionsGive a RE equivalent to the DFA below. Use the incremental process, from class, of removing states and growing REs at the remaining transitions. Show the intermediate (G)NFA after each state is removed.This is a cs question True or false ? Non determinism only applies in the direction of the transition, just because an 'a' forces you to be in two states does not mean you cannot be in just one of the two alone via some other path.
- When the DFA minimization algorithm merges states p and q, then a) p and q are dead-end states b) p is distinguishable from q c) p and q are start states d) p is equivalent to q e) p and q are not reachable from the start stateMake an assignment of state values to the three states x, w, and v in the state diagram below, e.g., x is 00. Give the truth table that is equivalent to the diagram and contains the columns p0, p1, b, n0, n1, and z, where p0p1 represents the present state and n0n1 represents the next state.Computer Science Which of these statements are true? In a deterministic autonoma, the transition function δ assigns each input symbol to a single state. In a deterministic finite autonoma, the transition relation δ assigns to each pair of a state and input symbol exactly one subsequent state.
- Give an example of a state space (you need to identify the initial state and the goal state in the state space) where the breadth-first strategy works faster than the depth-first strategy.Draw diagram of a Finite State Machine that accept words defined by the following regular expression: a(a|b)∗a Remember, a machine accepts a word if sequence of transitions will lead to an accepting state. Hint: from start, machine reads characters and stays in undecided state or moves to accepted state.Carry out the bisimulation colouring algorithm step-by-step on the labelled transition system defined by thefollowing process definition, and use this to provide an equivalent system with a minimal number of states.X def= a.Y + a.(a.Z + b.W) Z def= a.Z + b.WY def= a.Y + a.Z + b.W W def= a.W how to draw that part: X def= a.Y + a.(a.Z + b.W)
- Computer Science You are told that state machine A has one input x, and one output y, both with type {1, 2}, and that it has states {a, b, c, d}. You are told nothing further. Do you have enough information to construct a state machine B that simulates A? If so, give such a state machine, and the simulation relation.Question: For each of the below three problems, draw the state diagram of a pushdown automaton. (a) {ww starts and ends with same symbol } (b) {w the length of w is odd } (c) {w\w = WR, i.e., w is a palindrome }. For instance the word noon is a palindrome because reversing the letters results in the same word.Correct answer will be upvoted else downvoted. Computer science. in case there are two planes and a molecule is shot with rot age 3 (towards the right), the cycle is as per the following: (here, D(x) alludes to a solitary molecule with rot age x) the primary plane delivers a D(2) to the left and lets D(3) progress forward to the right; the subsequent plane delivers a D(2) to the left and lets D(3) progress forward to the right; the primary plane lets D(2) forge ahead to the left and creates a D(1) to the right; the subsequent plane lets D(1) progress forward to one side (D(1) can't create any duplicates). Altogether, the last multiset S of particles is {D(3),D(2),D(2),D(1)}. (See notes for visual clarification of this experiment.) Gaurang can't adapt up to the intricacy of the present circumstance when the number of planes is excessively huge. Help Gaurang find the size of the multiset S, given n and k. Since the size of the multiset can be extremely huge, you…