Draw a wait for graph to detect deadlock in given situation.
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Draw a wait for graph to detect deadlock in given situation.
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- In the event of an impasse, it becomes necessary to terminate said processes, thereby leading to the subsequent consequences:A segment of code that cannot be entered and executed by more than one process at the same time is called _________________. deadlock critical section semaphore mutex A process that does not enter a critical section but also prevents other processes from entering is creating _______________. deadlock mutual exclusion lockout starvation Multiple processes that block each other indefinitely from entering a critical section are creating _____________. mutual exclusion starvation deadlock logout Using semaphores. s = 0 initially.Process p1 executes the sequence: P(s); V(s); P(s); V(s);Process p2 executes the sequence: V(s); V(s); P(s); V(s); After both processes terminate, s=________. 3 1 0 2 A monitor is a low-level kernel function that implements a priority queue. True or false Processes can access and modify monitor variables without having to call the monitor's functions. True False The correct monitor implementation of c.wait…There are two methods available for terminating processes and, accordingly, overcoming deadlocks:
- Can a single-threaded process deadlock by itself? Please elaborate on your answer.please select only correct option : 1) In ………………. only one process at a time is allowed into its critical section * a, Synchronization b, Mutual Exclusion c, Deadlock d, All of the given 2) To avoid race condition, ____ process(es) at a time can manipulate the shared variable. * a, One b, Two c, Three d, None 3) Process synchronization can be done through * a, Hardware b, Software c, Both Hardware and Software d, None of the given 4) For better memory-space utilization ________ is used a, Dynamic loading b, Static loading c, Dynamic linking Static linking d, All of the given 5) Peterson algorithm is restricted to ___ processes * a, One b, Three c, Five d, None of the givenTerminating processes and breaking deadlocks are accomplished via the use of two different ways.
- Suppose we have three processes P0, P1, and P2. Process P0 executes statement S0 and process P1 executes statement S1 and process P2 executes statement S2. Use wait and signal to ensure the following: S2 is always executed before S1 and S1 is always executed before S0S0.2) ______ is a situataion where one process is withheld due to other process. a) multi operating b) dead lock c) multi-programmingA system has three processes (P1,P2, P3) and three resources (R1,R2, R3). There is one instance of R1 and R2. There are three instances of R3. P1 holds an R1 and is requesting an R3. P2 holds an R3 and is requesting an R1. P3 holds two instances of R3 and an R2. Does a deadlock exist? Justify your answer.
- There are two techniques for stopping processes and resolving impasses:It is recommended that, in the event of a standstill, those processes be terminated, which will result in the following outcomes:ProcessBurst Time Priority Arrival TimeP1 10 3 0P2 1 1 0P3 2 5 0P4 1 4 0P5 5 2 0For the set of processes directly above, draw a Gantt chart for the FCFS Scheduling Algorithm.