Draw the product(s) of the following reactions. Na / NH3() -CEC-CH, • Consider E'Z stereochemistry of alkenes. Separate multiple products using the + sign from the drop-down menu. • If no reaction occurs, draw the organic starting material.
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- draw the two possible carbocations that can form when this alkene reacts with a strong acid (such as HBr or H3O+). of the two structures you drew, circle the more stable carbocation4-Chloro-2-pentene has a double bond that can have either the E or the Z configuration and a stereogenic center that can have either the R or the S configuration. How many stereoisomers arepossible altogether? Draw the structure of each, and group the pairs of enantiomers.Draw the organic product(s) of the following reaction. You do not have to consider stereochemistry. Include cationic counter-ions, e.g., Na+ in your answer, but draw them in their own sketcher. If no reaction occurs, draw the organic starting material. Separate multiple products using the + sign from the drop-down menu.
- Draw eugenol as a line structure. The double bonds of the benzene ring are fairly unreactive unless you use special catalysts. But the double bond on the side group is reactive. Draw the mechanism of eugenol reacting with HBr to form the two possible carbocation intermediates. Put your intermediates into square brackets. Label each carbocation as a methyl carbon or 1°, 2°, or 3°. Then circle a more stable carbocation if one is more stable. Can you guess what the final product is?Using dash–wedge notation to designate stereochemistry, draw (R)-pentane-1,2-diol.What are the reagents used to convert 2-butyne to C4H8? What are the products when that C4H8 is mixed with OsO4, and H2O (the formula will be C4H10O2 racemic)? What is the product when C4H8 is mixed with RCO3H, and H2O (the formula will be C4H10O2 meso)?
- When carbonyl compounds are reduced with a reagent such as LiAlH4 or NaBH4 and a new stereogenic center is formed, what will the composition of the product mixture be? Forms more of one enantiomer than another because of steric reasons around the carbonyl Forms more of one enantiomer than another depending on the temperature of the reaction Forms different products depending on the solvent used Forms a racemic mixture of the two possible enantiomersBased on the hydrogenation and the bromination reaction information, how many different alkene structures can you draw that could be Compound X? (If enantiomers are possible, count each pair of enantiomers as one structure.)Complete the following reactions by identifying the major organic product, reagent(s), or reactant. • If the product is a single compound, draw the structure clearly in the box. • List missing reagents neatly around the blue arrows. There may be more than one reagent per arrow. • If the product is a racemic mixture, clearly draw one enantiomer and write "racemic" under the answer.
- The heat of hydrogenation of cis-2,2,5,5-tetramethyl-3-hexene is -154 kJ (-36.7 kcal)/ mol, while that of the trans isomer is only -113 kJ (-26.9 kcal)/mol. Q.) Why is the heat of hydrogenation of the cis isomer so much larger (more negative) than that of the trans isomer?Draw the structure of cis-4,4-dimethylpent-2-ene. Hint: You may have to delete bond to get the right stereochemistry.Take 1-methylcyclohexene as the alkene and treat it with the reagent.