Question
Asked Nov 1, 2019

During the time 0.325 mol of an ideal gas undergoes an isothermal compression at 22.0∘C, 392 J of work is done on it by the surroundings. If the final pressure is 1.76 atm, what was the initial pressure?

What is the pV-diagram for the process?

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Expert Answer

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Step 1

Given information:

n= 0.325 mol
(work done on the system is negative)
W -392J
11
P 1.76 atm
f
R 8.314 J/mol K
T 22° C
(22+273) K
295 K
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n= 0.325 mol (work done on the system is negative) W -392J 11 P 1.76 atm f R 8.314 J/mol K T 22° C (22+273) K 295 K

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Step 2

Here, R is the universal gas constant.

Write the formula for work done in the isothermal process and...

Р.
W = nRT In
Р,
Р.
W
In
P
nRT
P Pe
nRT
-392J
J
(295 K)
(0.325 mol 8.314
mol-K
P (1.76 atm)e
P 1.08 atm
help_outline

Image Transcriptionclose

Р. W = nRT In Р, Р. W In P nRT P Pe nRT -392J J (295 K) (0.325 mol 8.314 mol-K P (1.76 atm)e P 1.08 atm

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