dx 21) Using half angle substitution, f. the new integral expression becomes 1-sin 2x-cos 2x 2da B. S (-1) da С. f da 22(-1) da D.S: 22(2+1) -1)

Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter8: Conic Sections
Section8.2: More Parabolas And Some Circles
Problem 63.2PS: By expanding (xh)2+(yk)2=r2, we obtain x22hx+h22ky+k2r2=0. When we compare this result to the form...
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dx
21) Using half angle substitution, f-
,the new integral expression becomes
1-sin 2x-cos 2x
2dz
dz
dz
dz
A. S
z(z-1)
В.
Z(2-1)
C. S:
22(z-1)
rx+1
22) fo S xdydx=?
A. 1/3
В. У
С. 3/2
D. 5/6
Transcribed Image Text:dx 21) Using half angle substitution, f- ,the new integral expression becomes 1-sin 2x-cos 2x 2dz dz dz dz A. S z(z-1) В. Z(2-1) C. S: 22(z-1) rx+1 22) fo S xdydx=? A. 1/3 В. У С. 3/2 D. 5/6
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