dx 6. [- xIn x sin 5tdt 7. V1+ cos 5t

Q: dy 3. dx cosx – ysinx = sin2x

A:

Q: d²y Find С. dx? 1. y= sin 2x +cos² x sin x 2. у- - y= 1-cosx

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Q: dy 3. dx y – x + cos - -

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Q: dy Find the General and Particular solution of = 8 sin 4x ; y = 6 when x = 0 dx

A: Given that : The differentiable equation dydx = 8 sin 4x . y = 6 when x = 0.

Q: 5 dx Find dx, x> V25x? -9 5x In 25x2-9 + C 3. sin-13x+c 1+9x2 +3x|+c 1 V1+9x? + C 3x 3. + C V25x2 -9…

A: The solution is given below in the next step:

Q: d²y Find 2 dx? y = sin 2x+cos² x

A: Using derivatives.

Q: Q1) Solve 1 + cos y – 2xy) dx – (xsin y + x²)dy = 0 +1

A: Given differential equation is  1x2+1+cosy-2xydx-xsiny+x2dy=0 This equation can be written as…

Q: 2FI 2FI sım nx dx = cos nx dx = 0, where n integer. 0.-

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Q: 3 tan-(x)dx O V3 - In (8) V3 TL In (4) 2/3 2.

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Q: x sin wx dx x2 + 6x + 10 Show that (2 sin 3w – 3 cos 3w) w > 0 %3D - 2e2w

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Q: 3r cos(x) 1. Evaluate dx V1+ sin(x)

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Q: -. Solve for dy/dx a. y = *+ sinx cos x † Sin X

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Q: b. sin 2xdy – 2(y - cosx)dx = 0; when x = 1/4, y = 0

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Q: T/2 S cos (x) sin°(x) dx = %3D

A: Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: dx3 dx =| V9-x² cos? 1+sin x .2 dx = 4. 5. 6.

A: (4)∫xx-1dxLet x-1=udx=du=∫u+1udu=∫1 du +∫1udu=u+lnuu=x-1 therefore∫xx-1dx= (x-1)+ln(x-1)+ C

Q: dy/dx= 4 cos 4x

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Q: 2- X %3D +2 3- Coshx dy +(y sinh x+e) dxo 36

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Q: dx 2. S; 3 cos x+4 sin x

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Q: COSX sin x dx 4. S 1-ఆశి అరికి న

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Q: 211 sin nx dx [ [1-cos2nx]dx t, where n %3D

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Q: S(6Vx + 3 cos x - 8)dx

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Q: dx (2) 3y sin x - -2xy cos x = 0 dy

A: Follow the procedure given below.

Q: "/2 sin x dx Jn/a V1-2 cos x 4.

A: As per the guidelines  we can answer only one question at a time. If you want to get the answers  of…

Q: (4e²+7x°+5 cos z + 2)dx

A: Solve integration

Q: dy 4 sin 2x, y = 2, when x = 1/2 dx

A:

Q: Q.2: Find dx 2) | (cos²x sinx )dx

A:

Q: Can you help me step by step?

A: The derivative of a function is computed as follows.

Q: d 1. sinx dx = - cos x + C because (- cos x+C) = _ dx

A: The first question is ∫sin(x)dx=-cos(x)+C

Q: 2 S² T ㅠ 1-cos x dx 2

A:

Q: 3. Evaluate 2y²sinxy dy dx 4. Evaluate , S sin(x² + y²) dy dx

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Q: 6) F Sin12y Cos’ y dy

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Q: 3- dx for y x sinx is equal to: a)2x cosx b) 2x sinx + cosx 2x c)x cosx+ sinx 2x

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Q: dy 4. Find at (- 2,0), if 3x² +2x²y² +sin y=12+2y. dx

A: NOTE: Refresh your page if you can't see any equations. . take derivative

Q: B) Find dx dzy and if x = sin 3z and y = tan23z dx2

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Q: Q5// Evahate dx 1- J- V&r-x 6co(3x2) dx dx sin - sinx

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Q: x7+3x2. Find dy/dx if: (y)² = sin (cos³(* +3: *)) %3D 2

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Q: J dx sin3(4x)

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Q: -3π/2 2. S TL √sinx + 1 cos x dx

A: We solve the given definite integral by using substitution method .

Q: S2(cosx)(sin2x)dx %3D 3.

A: .................(1) take  put all values in equation 1

Q: 4. J S (esc²a – co sec 0 tand) d0 - -

A: Explained below...

Q: 1 dx J 3 sin x+4 cos x+3

A:

Q: dy/dx of y=5^cos(3x+5)

A:

Q: 5. Sxcot°(10x²)dx 6. S ( tan (3z) dz cos*(3z)

A:

Q: d?s sin 3t + cos 3t dt2

A: Explanation of the answer is as follows

Q: +3x2. Find dy/dx if: (y)² = sin5(cos³(- -)) 2 %3D

A: Given: (y)2=sin5cos3x7+3x22 ----(1) To find: dydx Let u=x7+3x22 , v=cos3u w=sin5v Now equation (1)…

Q: 3. Find dy dx y= 3 Sin.

A: Find derivative

Q: Q2: (a) Evaluate ſ cosx sinx V1 – sin4x dx.

A:

Q: dy = 4 cos 4x dx

A: The given differential equation is dydx=4cos4x. We can solve this differential equation using…

Q: x² (d) S √1-4x² (HINT: sin² t = dx. (1. (1 - cos 2t).)

A: We have to evaluate ∫x21-4x2 dx.

Q: 7. Find (a) y = (x* + 5x) cos 5x %3D dx

A: We can find the derivative using product rule as below

Rate of Change

The relation between two quantities which displays how much greater one quantity is than another is called ratio.

Slope

The change in the vertical distances is known as the rise and the change in the horizontal distances is known as the run. So, the rise divided by run is nothing but a slope value. It is calculated with simple algebraic equations as: